Regardless of the dividend (the number being divided), no divisor can produce a remainder equal to, or greater than, itself..... dividing by 4 cannot result in a remainder of 5, for example, Therefore the only single-digit number which can return a remainder of 8 is 9. 35 ÷ 9 = 3 and remainder 8
mathematics
Find the quotient
9. The divisor must be greater than the remainder. A 1 digit divisor that is greater than 8 can only be 9.
To find how many two-digit numbers ( n ) result in a remainder of 4 when dividing 109, we can express this mathematically as ( 109 \equiv 4 \mod n ). This simplifies to ( 109 - 4 = 105 ) being divisible by ( n ), or ( n ) being a divisor of 105. The divisors of 105 that are two-digit numbers are 15, 21, 35, and 105, giving us a total of 4 two-digit divisors.
109 is a prime number. Therefore, the only divisors are 1and 109.
A 2 digit number divided by a four digit number, such as 2345, will leave the whole 2-digit number as a remainder. It cannot leave a remainder of 1.
I think you mean, the largest four digit number that has exactly three divisors. 2X3X1663=9,978
1, 2, 3, 5, 6, 7 and 9
The single-digit divisors of 7,000 are 1, 2, 4, 5, 7, 8.
The process of multiplication doesn't produce remainders.The process of division does.If you want to divide a 3-digit number by a one-digit numberand get a remainder of 8, try these:107 divided by 9116 divided by 9125 divided by 9134 divided by 9143 divided by 9..Add as many 9s to 107 as you want to, and then divide the result by 9.The remainder will always be 8.
The single digit divisors of 420 are: 1,2,3,4,5,6, and 7