Best Answer

Improved Answer:-

If: 2x+y = 5 and x^2 -y^2 = 3

Then by rearranging: y = 5 -2x and -3x^2 -28+20x = 0

Solving the above quadratic equation: x = 2 and x = 14/3

By substitution points of intersection are: (2, 1) and (14/3, -13/3)

Q: What are the points of intersection of the line 2x plus y equals 5 with x squared minus y squared equals 3 on the Cartesian plane showing work?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

Points of intersection work out as: (3, 4) and (-1, -2)

The points of intersection are: (7/3, 1/3) and (3, 1)

They intersect at the point of: (-3/2, 11/4)

If: x+y = 7 and x2+y2 = 25 Then: x = 7-y and so (7-y)2+y2 = 25 => 2y2-14y+24 = 0 Solving the quadratic equation: y = 4 and y = 3 By substitution points of intersection: (3, 4) and (4, 3)

No, in the Cartesian coordinate system it would show a vertical line whose intersection of the x-axis is 4.

Related questions

Points of intersection work out as: (3, 4) and (-1, -2)

It is the Cartesian equation of an ellipse.

The points of intersection are: (7/3, 1/3) and (3, 1)

It works out that the point of intersection is at (-4, -3.5) on the Cartesian plane.

The points are (-1/3, 5/3) and (8, 3).Another Answer:-The x coordinates work out as -1/3 and 8Substituting the x values into the equations the points are at (-1/3, 13/9) and (8, 157)

The points of intersection of the equations 4y^2 -3x^2 = 1 and x -2 = 1 are at (0, -1/2) and (-1, -1)

They intersect at the point of: (-3/2, 11/4)

If: y = 4x2-2x-1 and y = -2x2+3x+5 Then: 4x2-2x-1 = -2x2+3x+5 And so: 6x2-5x-6 = 0 Using the the quadratic equation formula: x = -2/3 and x = 3/2 Substitution: when x = -2/3 then y = 19/9 and when x = 3/2 then y = 5 Points of intersection: (-2/3, 19/9) and (3/2, 5)

If: x+y = 7 and x2+y2 = 25 Then: x = 7-y and so (7-y)2+y2 = 25 => 2y2-14y+24 = 0 Solving the quadratic equation: y = 4 and y = 3 By substitution points of intersection: (3, 4) and (4, 3)

No, in the Cartesian coordinate system it would show a vertical line whose intersection of the x-axis is 4.

Straight line: 3x-y = 5 Curved parabola: 2x^2 +y^2 = 129 Points of intersection works out as: (52/11, 101/11) and (-2, -11)

They work out as: (-3, 1) and (2, -14)