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Improved Answer:-

If: 2x+y = 5 and x^2 -y^2 = 3

Then by rearranging: y = 5 -2x and -3x^2 -28+20x = 0

Solving the above quadratic equation: x = 2 and x = 14/3

By substitution points of intersection are: (2, 1) and (14/3, -13/3)

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Q: What are the points of intersection of the line 2x plus y equals 5 with x squared minus y squared equals 3 on the Cartesian plane showing work?
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