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Where are the points of intersection of the equations 4y squared -3x squared equals 1 and x -2y equals 1?
Wiki User
∙ 7y ago
The points of intersection of the equations 4y^2 -3x^2 = 1 and x -2 = 1 are at (0, -1/2) and (-1, -1)
Wiki User
∙ 7y ago
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When graphing a system of equations what is the point of intersection called?
The points of intersection are normally the solutions of the equations for x and y
Where are the points of intersection of the parabolas y equals x squared plus 3x -10 and y equals -x squared -8x -15 when plotted on the Cartesian plane?
If: y = x^2 +3x -10 and y = -x^2 -8x -15 Then: x^2 +3x -10 = -x^2 -8x -15 Transposing terms: 2x^2 +11x +5 = 0 Factorizing the above: (2x +1)(x +5) = 0 meaning x = -1/2 or -5 Therefore by substitution points of intersection are at: (-1/2, -45/4) and (-5, 0)
How the solution of a linear system with two equations is represented by the point where the graphs of the two equation intersect?
The first graph consists of all points whose coordinates satisfy the first equation.The second graph consists of all points whose coordinates satisfy the second equation.The point of intersection lies on both lines so the coordinates of that poin must satisfy both equations.
What is y equals x squared?
it will form a parabola on the graph with the vertex at point (0,0) and points at (1,1), (-1,1), (2,4), (-2,4)......
What are the points of intersection of the equations of 3x minus 2y equals 1 and 3x squared minus 2y squared plus 5 equals 0 showing details of your work?
A: 3x-2y = 1 => 3x = 1+2y B: 3x2-2y2+5 = 0 => 3x2 = 2y2-5 Square both sides in equation A: 9x2 = 1+4y+4y2 Multiply all terms by 3 in equation B: 9x2 = 6y2-15 So it follows that:- 6y2-15 = 1+4y+4y2 and 6y2-15-1-4y-4y2 = 0 Collect like terms: 2y2-4y-16 = 0 Divide all terms by 2: y2-2y-8 = 0 Factorise: (y-4)(y+2) = 0 Therefore: y = 4 or y = -2 Substitute the above y values into the linear equation to find the values of x: The points of intersection are: (3, 4) and (-1,-2)
What are the points of intersection of the line x -y equals 2 with x squared -4y squared equals 5?
The points of intersection are: (7/3, 1/3) and (3, 1)
What are the points of intersection of 3x -2y -1 equals 0 with 3x squared -2y squared equals -5 on the Cartesian plane?
Points of intersection work out as: (3, 4) and (-1, -2)
What are the points of intersection of the parabolas of y equals 4x squared -12x -3 and y equals x squared plus 11x plus 5 on the Cartesian plane?
The points are (-1/3, 5/3) and (8, 3).Another Answer:-The x coordinates work out as -1/3 and 8Substituting the x values into the equations the points are at (-1/3, 13/9) and (8, 157)
When graphing a system of equations what is the point of intersection called?
The points of intersection are normally the solutions of the equations for x and y
What are the points of intersection between the equations of 3x -5y equals 16 and xy equals 7?
If 3x -5y = 16 and xy = 7 then by combining both equations into a single quadratic equation and solving it then the points of intersection are at (-5/3, -21/5) and (7, 1)
What are points of intersection of the line 3x -y equals 5 with the curve of 2x squared plus y squared equals 129?
Straight line: 3x-y = 5 Curved parabola: 2x^2 +y^2 = 129 Points of intersection works out as: (52/11, 101/11) and (-2, -11)
What are the points of intersection of the line y equals -8-3x with the curve y equals -2-4x-x squared?
They work out as: (-3, 1) and (2, -14)
What are the coordinates for x2 plus y2 equals 185 and x plus y equals 17?
We believe that those equations have no real solutions, and that their graphs therefore have no points of intersection.
What are the points of intersection between the equations of 2x plus y equals 5 and x2 -y2 equals 3?
It works out that the points of intersection between the equations of 2x+5 = 5 and x^2 -y^2 = 3 are at: (14/3, -13/3) and (2, 1)
What are the points of contact between the line 3x -2y equals 1 and the curve 3x squared -2y squared plus 5 equals 0?
Equations: 3x-2y = 1 and 3x^2 -2y^2 +5 = 0 By combining the equations into one single quadratic equation and solving it the points of contact are made at (3, 4) and (-1, -2)
What are the points of intersection between the line x -y equals 2 and the curve x2 -4y2 equals 5?
Equations: x -y = 2 and x^2 -4y^2 = 5 By combining the equations into a single quadratic equation in terms of y and solving it: y = 1/3 or y = 1 By means of substitution the points of intersection are at: (7/3, 1/3) and (3, 1)
What is the place where 2 curves meet?
The points of intersection. The coordinates of such points will be the solutions to the simultaneous equations representing the curves.
