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They intersect at the point of: (-3/2, 11/4)

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Q: What is the point of intersection of the parabolas of y equals 3x squared plus 10x plus 11 and y equals 2 -2x -x squared?

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You need two, or more, curves for points of intersection.

1,6

If: y = 3x^2 +10x +11 and y = 2 -2x -x^2 Then: 3x^2 +10x +11 = 2 -2x -x^2 Transposing terms: 4x^2 +12X +9 = 0 Factorizing the above: (2x+3)(2x+3) = 0 meaning x = -3/2 By substitution into original equations intersection is at (-3/2, 11/4)

The intersection is (-2, 6)

2

Related questions

If: y = x2+20x+100 and x2-20x+100 Then: x2+20x+100 = x2-20x+100 So: 40x = 0 => x = 0 When x = 0 then y = 100 Therefore point of intersection: (0, 100)

You need two, or more, curves for points of intersection.

1,6

If: y = 3x^2 +10x +11 and y = 2 -2x -x^2 Then: 3x^2 +10x +11 = 2 -2x -x^2 Transposing terms: 4x^2 +12X +9 = 0 Factorizing the above: (2x+3)(2x+3) = 0 meaning x = -3/2 By substitution into original equations intersection is at (-3/2, 11/4)

The intersection is (-2, 6)

It works out that the point of intersection is at (-4, -3.5) on the Cartesian plane.

2

The coordinates of the point of intersection is (1,1).

(2, -2)

3

A parabola is a type of graph that is not linear, and mostly curved. A parabola has the "x squared" sign in it's equation. A parabola is not only curved, but all the symmetrical. The symmetrical point, the middle of the parabola is called the vertex. You can graph this graph with the vertex, x-intercepts and a y-intercept. A parabola that has a positive x squared would be a smile parabola, and the one with the negative x squared would be a frown parabola. Also, there are the parabolas that are not up or down, but sideways Those parabolas have x=y squared, instead of y = x squared.

The point of intersection.

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