If: x^2+y^2+4x+6y -40 = 0 and x -y = 10
Then by rearranging: x = 10+y and 2y^2+30y+100 = 0
Solving the above quadratic equation: y = -10 and y = -5
Points of intersection by substitution are: (0, -10) and (5, -5)
If: x-2y = 8 and xy = 24 Then: x = 8+2y and so (8+2y)y = 24 => 8y+2y2-24 = 0 Solving the quadratic equation: y = -6 or y = 2 By substitution points of intersection: (-4, -6) and (12, 2)
If: x+y = 7 and x2+y2 = 25 Then: x = 7-y and so (7-y)2+y2 = 25 => 2y2-14y+24 = 0 Solving the quadratic equation: y = 4 and y = 3 By substitution points of intersection: (3, 4) and (4, 3)
If: y = 4x2-2x-1 and y = -2x2+3x+5 Then: 4x2-2x-1 = -2x2+3x+5 So: 6x2-5x-6 = 0 Solving the quadratic equation: x = -2/3 or x = 3/2 Points of intersection by substitution: (-2/3, 19/9) and (3/2, 5)
If: 3x-y = 5 and 2x2+y2 = 129 Then: x = 5/3+y/3 and so 2(5/3+y/3)2+y2 = 129 => 50+20y+2y2+9y2 = 1161 Therefore: 11y2+20y-1111 = 0 Solving the quadratic equation: y = -11 or y = 101/11 By substitution points of intersection are: (-2, -11) and (52/11, 101/11)
Points: (7, 5) Equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Equations intersect at: (4, 1) Length of perpendicular line: 5
Many teams have recorded 0 points in the champions league group stages. But Milan have recorded 5 points and still qualified to the next round. that is the record.
1 Equation: y = 2x+10 2 Perpendicular equation works out as: 2y = -x+10 3 Point of intersection: (-2, 6) 4 Distance is the square root of: (-2-2)2+(6-4)2 = 2 times sq rt of 5
you just need more goals than the opponent
Points: (4, -2) Equation: 2x-y-5 = 0 Perpendicular equation: x+2y = 0 Equations intersect at: (2, -1) Perpendicular distance is the square root of: (2-4)2+(-1--2)2 = 5 Distance = square root of 5
Eqn (A): => 2x + 5y = 16 Eqn (B): => 5x + 2y = -2 5*Eqn (A) - 2*Eqn (B): 21y = 84 => y = 4 Substituting for y in Eqn (a): x = -2
The Tour de France uses a points system to reward riders for their performance in various stages and competitions throughout the race. Points are awarded based on finishing positions in both individual stages and the overall classification, with higher placements earning more points. Additionally, points are given for intermediate sprints and for the best sprinters in the green jersey competition. This system encourages competitive racing and rewards consistency and speed across different stages.
The succession stages differ from primary succession as the stages are nothing more than mere points of succession. Meanwhile, primary succession is considered to be a complete success and not just a point in success.