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There are an infinite number of positive integers divisible by 3, 5, and 7. This is because there is no limit to numbers and they go on indefinitely in both a positive and a negative direction.
No, positive integers ending with the digit 5 are divisible by 5.
To find how many positive integers less than or equal to 10,000 are divisible by 2, 5, or 10, we can use the principle of inclusion-exclusion. The count of integers divisible by each is: Divisible by 2: ( \frac{10000}{2} = 5000 ) Divisible by 5: ( \frac{10000}{5} = 2000 ) Divisible by 10: ( \frac{10000}{10} = 1000 ) Applying inclusion-exclusion, we have: [ 5000 + 2000 - 1000 = 6000 ] Thus, there are 6000 positive integers less than or equal to 10,000 that are divisible by 2, 5, or 10.
6
There are 130 positive integers less than 1,000 that are divisible by seven but not divisible by 11
533
105, 210, 315 and so on.
All positive integers are divisible by one.
yes. Negative integers could divisible by 5.
To find the number of positive integers less than 1001 that are divisible by either 2 or 5, we use the principle of inclusion-exclusion. First, the count of integers divisible by 2 is ( \left\lfloor \frac{1000}{2} \right\rfloor = 500 ), and those divisible by 5 is ( \left\lfloor \frac{1000}{5} \right\rfloor = 200 ). The count of integers divisible by both 2 and 5 (i.e., by 10) is ( \left\lfloor \frac{1000}{10} \right\rfloor = 100 ). Thus, the total is ( 500 + 200 - 100 = 600 ). Therefore, there are 600 positive integers less than 1001 that are divisible by either 2 or 5.
All negative integers ending in 5 and 0 are divisible by 5.
To find how many positive integers less than 100 are divisible by 3, 5, and 7, we first calculate their least common multiple (LCM). The LCM of 3, 5, and 7 is 105. Since 105 is greater than 100, there are no positive integers less than 100 that are divisible by all three numbers. Therefore, the answer is 0.