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How many positive integers are divisible by 3 5 and 7?
There are an infinite number of positive integers divisible by 3, 5, and 7. This is because there is no limit to numbers and they go on indefinitely in both a positive and a negative direction.
Is 455 a prime number?
No, positive integers ending with the digit 5 are divisible by 5.
How many positive integers less than 200 are divisible by 2 3 5?
6
How many positive integers less than 1000 are divisible by 7 and are not divisible by 11?
There are 130 positive integers less than 1,000 that are divisible by seven but not divisible by 11
What is the number of positive integers less than 6000 which are divisible by 5 but not by 9?
533
What positive integers are divisible by 3 5 and 7?
105, 210, 315 and so on.
What is a divisible by 1?
All positive integers are divisible by one.
Negative integers that are divisible by 5?
yes. Negative integers could divisible by 5.
How many positive integers less than 1001 are divisible by either 2 or 5 or both?
To find the number of positive integers less than 1001 that are divisible by either 2 or 5, we use the principle of inclusion-exclusion. First, the count of integers divisible by 2 is ( \left\lfloor \frac{1000}{2} \right\rfloor = 500 ), and those divisible by 5 is ( \left\lfloor \frac{1000}{5} \right\rfloor = 200 ). The count of integers divisible by both 2 and 5 (i.e., by 10) is ( \left\lfloor \frac{1000}{10} \right\rfloor = 100 ). Thus, the total is ( 500 + 200 - 100 = 600 ). Therefore, there are 600 positive integers less than 1001 that are divisible by either 2 or 5.
What are the negative integers divisible by 5?
All negative integers ending in 5 and 0 are divisible by 5.
How many positive integers with exactly three decimal digit positive integers between 100 and 999 inclusive divisible by 7?
Of the 729 numbers that satisfy the requirement of positive integers, 104 are divisible by 7.
How many positive integers less than 100 are divisible-by 3 5 and 7?
To find how many positive integers less than 100 are divisible by 3, 5, and 7, we first calculate their least common multiple (LCM). The LCM of 3, 5, and 7 is 105. Since 105 is greater than 100, there are no positive integers less than 100 that are divisible by all three numbers. Therefore, the answer is 0.
