105, 210, 315 and so on.
No, positive integers ending with the digit 5 are divisible by 5.
One of the infinitely many integers divisible by 2, 3 and 5 is 3000.
533
yes. Negative integers could divisible by 5.
There are 1602 integers.
There are an infinite number of positive integers divisible by 3, 5, and 7. This is because there is no limit to numbers and they go on indefinitely in both a positive and a negative direction.
6
No, positive integers ending with the digit 5 are divisible by 5.
10 20 30 40 50...
One of the infinitely many integers divisible by 2, 3 and 5 is 3000.
533
yes. Negative integers could divisible by 5.
There are 1602 integers.
All negative integers ending in 5 and 0 are divisible by 5.
To find the number of positive integers less than 1001 that are divisible by either 2 or 5, we use the principle of inclusion-exclusion. First, the count of integers divisible by 2 is ( \left\lfloor \frac{1000}{2} \right\rfloor = 500 ), and those divisible by 5 is ( \left\lfloor \frac{1000}{5} \right\rfloor = 200 ). The count of integers divisible by both 2 and 5 (i.e., by 10) is ( \left\lfloor \frac{1000}{10} \right\rfloor = 100 ). Thus, the total is ( 500 + 200 - 100 = 600 ). Therefore, there are 600 positive integers less than 1001 that are divisible by either 2 or 5.
Positive integers are 1, 2, 3, 4, 5, 6 ....
19 divisible by 5, 14 divisible by 7. Of these, 3 divisible by both.