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The number of possible 3 digit combinations you can make out of 1-9 with out

repeated digits is:

9C3 = 9!/(3!(9-3)!) = 84

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Q: What are the possable 3 digit combinations you can make out of 1-9?
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How many 3 digit combinations are there in 1 to 21?

I am assuming you mean 3-number combinations rather than 3 digit combinations. Otherwise you have to treat 21 as a 2-digit number and equate it to 1-and-2. There are 21C3 combinations = 21*20*19/(3*2*1) = 7980 combinations.


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