It depends which one digit numbers are used. The ten can be any digits from -9 to 9, covering 19 different numbers. If you pick one of those 19 numbers ten times that would be 6131066257801 different possibilities of the number of one digit sets you could make.
19*19*19*19*19*19*19*19*19*19=6131066257801
362,880 edit: 3,628,800 edit: Sorry, Whizkid. You included '10', whereas the question clearly stated "single-digit numbers". Now that we think about it, the "10 single digit numbers" must include zero, so the product is zero. But for the digits 1 thru 9, the product is still 362,880 .
Zero. Any five consecutive natural numbers will contain at least one multiple of 2 and at least one multiple of 5, meaning that the product will be a multiple of 10.
5 digit telephone numbers having at least one of their digits repeated is = total possible 5 digit telephone numbers - 5 digit telephone numbers without any digit being repeated. =(10*10*10*10*10)-(10*9*8*7*6) =100000-30240 =69760
10 because 10 is the first 2 digit number out of all numbers.
There is one significant digit in the number 10, as written.
-98
It is 0.
Due to carries, in the multiplication a zero can change to a non-zero and vice versa.
362,880 edit: 3,628,800 edit: Sorry, Whizkid. You included '10', whereas the question clearly stated "single-digit numbers". Now that we think about it, the "10 single digit numbers" must include zero, so the product is zero. But for the digits 1 thru 9, the product is still 362,880 .
No one-digit numbers are divisible by 10. 10 is divisible by 1, 2 and 5.
Zero. Any five consecutive natural numbers will contain at least one multiple of 2 and at least one multiple of 5, meaning that the product will be a multiple of 10.
5 digit telephone numbers having at least one of their digits repeated is = total possible 5 digit telephone numbers - 5 digit telephone numbers without any digit being repeated. =(10*10*10*10*10)-(10*9*8*7*6) =100000-30240 =69760
10 because 10 is the first 2 digit number out of all numbers.
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
There is one significant digit in the number 10, as written.
There are 9 digits that can be the first digit (1-9); for each of these there is 1 digit that can be the second digit (6); for each of these there are 10 digits that can be the third digit (0-9); for each of these there are 10 digits that can be the fourth digit (0-9). → number of numbers is 9 × 1 × 10 × 10 = 900 such numbers.
9000. The first digit can be any one of 1-9 (9 choices). The second digit can be any one of 0-9 (10 choices). The third digit can be any one of 0-9 (10 choices). The fourth digit can be any one of 0-9 (10 choices). So, in all, 9*10*10*10 = 9000