It depends which one digit numbers are used. The ten can be any digits from -9 to 9, covering 19 different numbers. If you pick one of those 19 numbers ten times that would be 6131066257801 different possibilities of the number of one digit sets you could make.
19*19*19*19*19*19*19*19*19*19=6131066257801
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362,880 edit: 3,628,800 edit: Sorry, Whizkid. You included '10', whereas the question clearly stated "single-digit numbers". Now that we think about it, the "10 single digit numbers" must include zero, so the product is zero. But for the digits 1 thru 9, the product is still 362,880 .
Zero. Any five consecutive natural numbers will contain at least one multiple of 2 and at least one multiple of 5, meaning that the product will be a multiple of 10.
5 digit telephone numbers having at least one of their digits repeated is = total possible 5 digit telephone numbers - 5 digit telephone numbers without any digit being repeated. =(10*10*10*10*10)-(10*9*8*7*6) =100000-30240 =69760
10 because 10 is the first 2 digit number out of all numbers.
There is one significant digit in the number 10, as written.