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If you mean: y = kx-2 and y = x^2-8x+7

Then: x^2-8x+7 = kx-2

=> x^2-(8x-kx)+7+2 = 0

=> x^2-8x+kx+9 = 0

For the tangent to touch the curve the discriminant of b^-4ab must = 0

So: (8+k)^2-4*(9*1) = 0 => (8+k)^2 -36 = 0 => (8+k)^2 = 36

Square root both sides and then subtract 8 from both sides:

k = - or + 6 -8

Therefore possible values of k are: k = -2 or k = -14

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Q: What are the possible values of k when the line y equals kx -2 is a tangent to the curve y equals x squared -8x plus 7 showing work?
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