yes 1 + cot x^2 = csc x^2
0.5
There are 2 roots to the equation x2-4x-32 equals 0; factored it is (x-8)(x+4); therefore the roots are 8 & -4.
Calculate the derivative of the function.Use the derivative to calculate the slope at the specified point.Calculate the y-coordinate for the point.Use the formula for a line that has a specified slope and passes through a specified point.
As x ∝ yz2 then x = kyz2 where k is a constant. Substituting the given figures, 40 = k*20*22 = 80k Then k = ½ and the formula is, x = ½yz2 So, x = ½ * 30 *32 = 135
It is a function which maps the tangent ratio - any real value - to an angle in the range (-pi/2, pi/2) radians. Or (-90, 90) degrees.If tan(x) = y then x is the inverse tangent of y.It is also known as "arc tangent", and spreadsheets, such as Excel, use "atan" for this function.Warning:1/tangent = cotangent is the reciprocal, NOT the inverse.
x = 15.01, approx.
yes 1 + cot x^2 = csc x^2
The TI-83 does not have the cot button, however, if you type 1/tan( then this will work the same as the cot since cot=1/tan. The other way to do this is to type (cos(x))/(sin(x)) where x is the angle you're looking for. This works because cot=cos/sin
x = -32 Solution: -x = 32 -1 * -x = 32 * -1 x = -32
x = 74.05 degrees, approx
4
The question is suppose to read: Find the equation of the line tangent to y=(x²+3x)²(2x-2)³, when x=8
32 + x = 71 32 - 32 + x = 71 - 32 x = 39
32 cubed equals to 32768.
1 x 32, 2 x 16, 4 x 8 = 32
x + 32 = 55 x = 55 - 32 x = 23