The divisors of 63 are: 1, 3, 7, 9, 21, 63.
1, 3, 7, 9, 21, 63.
Prime divisors of 120 = 2, 4, 8, 3, 24, 5
293 only has two divisors because it is a prime number. The divisors are 1 and 293.
Since 7 is a prime, its only divisors are 1 and 7.
23 is a prime number. It has two divisors.
7 and 9 are divisors of 63.
29 is a prime number and so its only divisors are 1 and 29.
Since 11 is a prime number, its only divisors are 1 and itself.
Because five is a prime number its only divisors are 1 and itself.
yes. The only divisors of a prime number are itself and 1. Without counting the prime number, the sum of it's divisors is always 1.
13 is prime number therefore it only has two divisors 1 and 13