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Answered 2015-11-19 11:00:42

When the given expression equals 0 then x = -1/6 and x = -6

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What is 6x2-2x plus 36 equals 5x2 plus 10x?

6x2-2x+36 = 5x2+10x 6x2-5x2-2x-10x+36 = 0 x2-12x+36 = 0 (x-6)(x-6) = 0 x = 6 or x = 6 It has two equal roots.


What is 6xsquared plus 37x plus 6 equals 0 factored?

This equation can't actually be factored, but you can solve for x: 6x2 + 37x + 6 = 0 ∴ 6x2 + 37x = -6 ∴ x2 + (37/6)x = -1 ∴ x2 + (37/6)x + (37/12)2 = -1 - (37/12)2 ∴ (x + 37/12)2 = -1 - (37/12)2 ∴ x + 37/12 = ±[-1 - (37/12)2]1/2 ∴ x = 37/12 ±[-1 - (37/12)2]1/2 Which gives you two complex numbers for the answer, approximately: 37 / 12 + 3.2414417 × i 37 / 12 - 3.2414417 × i


What is (6x2) plus 3?

(6 × 2) + 3 = 15


Factor the trinomial 6x2-18x plus 12?

6x2-18x+12 = (6x-6)(x-2)


How do you list all factors of 6x2 plus 14x-12?

6x2 + 14x -12 = (3x - 2) (2x + 6). There they are.


Solve 6xsquared plus 10x equals 5?

6x2 + 10x = 5 6x2 + 10x - 5 = 0 The roots are 1/(2*6)* [-10 +/- sqrt(102 - 4*6*(-5))] = 1/(2*6) * [-10 +/- sqrt 220] =1/6 * [-5 +/- sqrt 55] So x = -2.0694 or 0.403


What is 34 plus 6x2?

34+(6*2)=34+12+46


What is the value of n in the expression x5 plus 4x4 minus 6x2 plus nx plus 2 that has a remaider of 6 when divided by x plus 2?

x5+4x4-6x2+nx+2 when divided by x+2 has a remainder of 6 Using the remainder theorem: n = 2


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6(x - 2)(x - 1)


X3 plus 6x2 - 4x - 24 factor completely?

x3 + 6x2 - 4x - 24 = (x + 6)(x2 - 4) = (x + 6)(x + 2)(x - 2)


-6 square roots of 3 plus 6 square roots of three?

It is: 0


What is the degree of 5 plus 6x2 plus 3x-7x3 plus x6?

5 + 6x² + 3x - 7x³ + x6 would have the degree of 6.


What is 6x squared plus 5x minus 6 factored out to?

6x2 + 5x - 6 is factored out to (2x + 3)(3x - 2).


How do you solve for x in the equation 3 over x square plus 3 over 4x minus 3 over 1 equals 6 over 2x square minus 6 over 3x plus 6 over 5?

3/(x2+4x-1) = 6/(2x2-3x+5) Cross - multiply in order to eliminate the fractions: 6*(x2+4x-1) = 3*(2x2-3x+5) 6x2+24x-6 = 6x2-9x+15 6x2-6x2+24x+9x = 15+6 33x = 21 x = 21/33 => x = 7/11


What are the rational roots of 3x3 plus x2-8x plus 6?

I do not believe that there are any rational roots.


How do you solve 6x2 plus 12x equals 0?

2x(3x+6) = 0 x = 0 or x = -2


What is the discriminant and the solution of y equals 6x2 plus x-1?

It is: 12-4(6*-1) = 25


What is the complete factorization of 6x2 plus 9x - 6?

Divide all terms by 3 and it is: (2x-1)(x+2)


What is 6 multilified by 4?

6 multiplied by 4 is 24 here is how i did it 6x1=6 6x2=12 (you just do 6 plus another 6) 6x3=18 6x4=24 hope this helped :)


What Are the roots of x2 plus 11x plus 30 equals 0?

x2 + 11x + 30 = 0 (x + 5)(x + 6) = 0 so the roots are -5 and -6


Factor 6x2 - 18x plus 12 as a polynomial in descending order?

First divide by 6: 6(x2 - 3x + 2) = 6(x - 1)(x - 2)


What is 6 x 2?

6x2= 12.


Factor the trinomial 6x2 plus 14x -12?

(3x - 2)(2x + 6) or 2(3x - 2)(x + 3)


Can someone explain to how find the real roots of x3 plus 6x2-5x-30 equals 0?

x = 2.236, -2.236 & -6. (to 3 decimal places)x3 + 6x2 - 5x - 30 = 0First of all, let us note that as the highest power in the polynomial is to the power of 3, we are expecting to find 3 roots (the real + imaginary roots will equal 3).Ok, so we need to factor the expression x3 + 6x2 - 5x - 30.There are different methods to try to factor an expression like this. We are going to split this down into 2 groups (because we can see that we will be able to factor each).1.x3 + 6x2 &2. -5x - 30. We can factor out the "-" (minus) here to become: - (5x + 30).So we have:(x3 + 6x2) - (5x + 30) = 0We can factor out "x2" from the first bracket and "5" from the second to get:x2 (x + 6) -5 (x + 6) = 0We can now see that "x + 6" is a common factor and so we can rewrite the original expression as:(x2 - 5) (x + 6) = 0Now we can solve for the roots of x by making each bracket equal to 0 in turn, so:x2 - 5 = 0x2 = 5x = 51/2 (we have two roots here of course: the square root of 5 & the square root of 5 times -1)x = 2.236 & -2.236 (to 3 decimal places only)&x + 6 = 0x = -6Thus all roots are real (none are imaginary) and they are: x = 2.236, -2.236 & -6.


What is 6 times x squared?

6 * x2 = 6x2