(6 × 2) + 3 = 15
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∙ 9y agoRearrange: 4x5 + 6x2 + 6x3 + 9 Group: 2x2 (2x3 + 3) + 3 (2x3 + 3) Simplify to get your answer: (2x2 + 3) (2x3 + 3)
9+6x2=21
6x2 + 9x = 0 3x(2x + 3) = 0 3x = 0 or 2x + 3 = 0 x = 0 or x = -3/2
7X^3 Third degree polynomial.
6x2=12 2x-28=?
6x2 + 11x + 3 = 6x2 + 9x + 2x + 3 = 3x(2x + 3) + 1(2x + 3) = (2x + 3)(3x + 1)
Rearrange: 4x5 + 6x2 + 6x3 + 9 Group: 2x2 (2x3 + 3) + 3 (2x3 + 3) Simplify to get your answer: (2x2 + 3) (2x3 + 3)
The expression may be : 6x2 + 17x + 12 This factors as, 6x2 + 17x + 12 = (3x + 4)(2x + 3) Or, the expression could be : 6x2 - 17x + 12 This factors as, 6x2 - 17x + 12 = (3x - 4)(2x - 3)
9+6x2=21
6x2 + 9x = 0 3x(2x + 3) = 0 3x = 0 or 2x + 3 = 0 x = 0 or x = -3/2
7X^3 Third degree polynomial.
6x2 + 10x = 2x(3x + 5)
6x2=12 2x-28=?
(2x^2 - 5)(4x^3 + 3)
6x2+13x-5 = 0 (2x+5)(3x-1) = 0 x = -5/2 or x = 1/3
-3(2x + 1)(4 + 3x) = -3[8x + 6x2 + 4 + 3x] = -3[6x2 + 11x + 4] = -18x2 - 33x - 12.
x3 - 6x2 + 4x + 15 = (x - 3)(x - (3/2 + √29/2))(x - (3/2 - √29/2)) ⇒ roots are x = 3, x = 3/2 + √29/2 (≈ 4.19), or x = 3/2 - √29/2 (≈ -1.19)