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There is no equation - only an expression. So there are no solutions (or solution intervals).
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One solution. (cos x)2 - 2cos x = 3 Factor: (cos x - 3)(cos x + 1)= 0 cos x = {-1, 3} Solve: For cos x = -1, x = 180 deg No solution for cos x = 3
how do you find the solution to x<3
2x2+5x-3 = 0 (2x-1)(x+3) = 0 x = 1/2 or x -3
There is no equation - only an expression. So there are no solutions (or solution intervals).
x+1=x+2 x=1+2+x 0x=1+2 0x=3 0x=/=3 (=/= means does not equal) so there is no solution
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An equation with the solution set 1 and 3 can be written in factored form as (x-1)(x-3) = 0. When expanded, this equation becomes x^2 - 4x + 3 = 0. Therefore, the equation x^2 - 4x + 3 = 0 has the solution set 1 and 3.
One solution. (cos x)2 - 2cos x = 3 Factor: (cos x - 3)(cos x + 1)= 0 cos x = {-1, 3} Solve: For cos x = -1, x = 180 deg No solution for cos x = 3
x2 + x + 1 = 0 ∴ x2 + x + 1/4 = -3/4 ∴ (x + 1/2)2 = -3/4 ∴ x + 1/2 = ± √(-3/4) ∴ x = - 1/2 ± (i√3) / 2 ∴ x = (-1 ± i√3) / 2
2x2-7x+3 = 0 (2x-1)(x-3) = 0 x = 1/2 or x = 3
Solution: x = 1/4 and x = -3.
y = x - 1 y - x = 3 y = x - 1 y = x + 3 Since both equations represent straight lines that have equal slopes, 1, then the lines are parallel to each other. That is that the lines do not intersect, and the system of the equations does not have a solution.
how do you find the solution to x<3
1a x 1a is the same as: a x a so... a x a= a^2 or a squared, if you had a x a x a, the solution would be a^3, or a cubed.