X2 - X - 6 = 0what two factors of - 6 add up to - 1 ?(X + 2)(X - 3)============(- 2, 0 ) and (3, 0 )------------------------------solution set of points
Linear inequalities are equations, but instead of an equal sign, it has either a greater than, greater than or equal to, less than, or a less than or equal to sign. Both can be graphed. Solving linear equations mainly differs from solving linear inequalities in the form of the solution. 1. Linear equation. For each linear equation in x, there is only one value of x (solution) that makes the equation true. Example 1. The equation: x - 3 = 7 has one solution, that is x = 10. Example 2. The equation: 3x + 4 = 13 has one solution that is x = 3. 2. Linear inequality. On the contrary, a linear inequality has an infinity of solutions, meaning there is an infinity of values of x that make the inequality true. All these x values constitute the "solution set" of the inequality. The answers of a linear inequality are expressed in the form of intervals. Example 3. The linear inequality x + 5 < 9 has as solution: x < 4. The solution set of this inequality is the interval (-infinity, 4) Example 4. The inequality 4x - 3 > 5 has as solution x > 2. The solution set is the interval (2, +infinity). The intervals can be open, closed, and half closed. Example: The open interval (1, 4) ; the 2 endpoints 1 and 4 are not included in the solution set. Example: The closed interval [-2, 5] ; the 2 end points -2 and 5 are included. Example : The half-closed interval [3, +infinity) ; the end point 3 is included.
You are looking for the solution to the function 2x - 3y = 7.This means that when you substitute 5 for x and 1 for y, the equation makes sense logically.(2*5) - (3*1) = 10 - 3 = 7.This makes sense logically.
Not necessarily, take for example the equation x^2=5-12i. Then, 3-2i satisfies the equation. However, 3+2i does not because (3+2i)^2 = 5+12i.
An equation may have zero, one, or more solutions (this is also true for a system of equations). The equation 2 + x = 5 has only solution, for example. x can only equal 3, so there is one solution. (An example of an equation with more that one solution is x2 = 4. In this case x can equal 2 or -2, so this equation has two solutions. An example of an equation with an infinite number of solutions is x + 6 = 3*2 + x. x can equal any number to make this equation true, so it has an infinite number of solutions. The equation x = x + 1 is an example of an equation with no solutions.)
It means a listing of every solution to an equation. Example 1: 3x + 1 = 10. Solution set: x is an element of the set {3}. That means there is just one solution. If you replace "x" in the original equation with "3", you get a true statement; if you replace it with anything else, you don't. Example 2: x2 = 25. Solution set: x is an element of the set {5, -5}.
Solution: x = 1/4 and x = -3.
There can be no solution to an algebra equation because of limitations of the domain. For example,x+3 = 2 has no solution if the domain for x is the set of positive integers,x*3 = 2 has no solution if the domain for x is the set of whole numbers,x^3 = 2 has no solution if the domain for x is the set of rational numbers,x^2 = -2 has no solution if the domain for x is the set of real numbers.Alternatively, the equation has no solution if it can be reduced to a false statement. For example,x + 2 = x + 3 can be simplified to 2 = 3 which is false and so there is no solution.
-2-1=-3
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If you mean: 9n = 3 then the value of n is 1/3 which is the solution to the equation
3
X2 - X - 6 = 0what two factors of - 6 add up to - 1 ?(X + 2)(X - 3)============(- 2, 0 ) and (3, 0 )------------------------------solution set of points
3x-1=0 set the equality to 03x=1 isolate the x term3x/3=1/3 divite both sides of the equation by the number that stays next to xx=1/3 get the answer ;))
A solution to an question makes the equation true. For example a solution to the equation 3x = x + 6 is x = 3, since 3(3) = 3+6.
There is no such pair. The solution to equation 1 and equation 2 is x = 1, y = 1. The solution to equation 2 and equation 3 is x = 1, y = 1. And the solution to equation 1 and equation 3 is any point on the line 3x + 2y = 5 - an infinite number of solutions. The fact that the determinant for equations 1 and 3 is zero (or that they are not independent) does not mean that there is no solution. It means that there is no UNIQUE solution. In this particular case, the two equations are equivalent and so have an infinite number of solutions.
No, to check if the values are a solution, substitute x=1 and y=3 into the equation and see if it holds true. In this case, when x=1 and y=3, the equation becomes 3(3) β 2(1) + 1, which simplifies to 9 β 3. So, 1,3 is not a solution to the equation 3y = 2x + 1.