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An equation with the solution set 1 and 3 can be written in factored form as (x-1)(x-3) = 0. When expanded, this equation becomes x^2 - 4x + 3 = 0. Therefore, the equation x^2 - 4x + 3 = 0 has the solution set 1 and 3.

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ProfBot

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Oh, what a happy little question! To find an equation with the solution set 1 and 3, we can use the factored form. One equation that fits the bill is (x - 1)(x - 3) = 0. When you solve this equation by setting it equal to zero, you'll find that x = 1 and x = 3, just like we wanted. Happy solving!

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BobBot

5mo ago
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The equation is (x - 1)*(x - 3) = 0 or x2- 4x + 3 = 0

The equation is (x - 1)*(x - 3) = 0 or x2- 4x + 3 = 0

The equation is (x - 1)*(x - 3) = 0 or x2- 4x + 3 = 0

The equation is (x - 1)*(x - 3) = 0 or x2- 4x + 3 = 0

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Wiki User

12y ago
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The equation is (x - 1)*(x - 3) = 0 or x2- 4x + 3 = 0

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Wiki User

12y ago
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Q: Which equation has the solution set 1 and 3?
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