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They are 40, 41 and 42.

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โˆ™ 2014-08-08 07:53:02
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Q: What are the three consecutive integers whose sum of 123?
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Related questions

What are the three consecutive integers whose sum is 123?

The integers are 40, 41 and 42.


Three consecutive odd integers whose sum is 123?

The numbers are 39, 41 and 43.


What are three consecutive odd integers with the sum of -123?

They are: -39 -41 -43 = -123


Three consecutive odd integers that have a sum of 123?

123/3 = 41 so integers are 39, 41 and 43


Find three consecutive even integers that have a sum of 123?

There are no consecutive even integers totaling 123 but there are two combinations of odd/even integers. They are 39, 41 and 43 as well as 40, 41 and 42.


3 consecutive odd integers whose sum is 123?

123/3 - 2, 123/3 and 123/3 + 2 ie 39, 41 and 43.


Find 2 consecutive odd integers that have a sum of 123?

There is a set of two consecutive integers that have a sum of 123; one odd and one even. They are 61 and 62.


What two consecutive whole numbers lie between the square root of 123?

between which two consecutive integers does the square root lie 123


Ind three consecutive odd integers that have a sum of 123?

x is lowest of the integers so x + (x + 2) + (x + 4) = 123 ie 3x + 6 = 123 so 3x = 117 and x = 39, so integers are 39, 41 and 43


Find 3 consecutive odd integers that have a sum of 123?

39,41,43! Ya


What are 3 consecutive integers that equal 366?

The numbers are 121, 122 and 123.


2 consecutive numbers whose sum is 123?

61 & 62


Find three consecutive integers whose sum is one hundred and twenty three?

You are told that:a + b + c = 123You are also told that:b = a + 1c = a + 2Therefore:a + (a + 1) + (a + 2) = 1233a + 3 = 1233a = 120a = 40Therefore, the numbers are 40, 41 and 42.


Find 2 consecutive numbers whose sum is 123?

62 & 61


What three consecutive odd integers have the sum of 123?

For three consecutive odd integers to have the sum 123, the equation N + N+2 + N+4 = 123 must be solvable with N being an odd integer.N + N+2 + N+4 = 1233N + 6 = 1233N = 117N = 39Since 39 is an odd integer, the solution is 39, 41, and 43.If N were even, or if N resolved to a non-integer, then the problem would have been incorrectly stated and unsolvable.


The sum of three consecutive numbers is 123 what are the numbers?

The numbers are 40, 41 and 42.


What are the first ten consecutive composite numbers?

The first ten consecutive composite positive integers are: 114 115 116 117 118 119 120 121 122 123


What are three consecutive numbers that add up to 369?

The numbers are 122, 123, 124 as well as 121, 123, 125.


What are three conesecutive odd integers that have a sum of 123?

39, 41 and 43. or 123/3 -2, 123/3 and 123/3 +2


What three consecutive odd numbers add up to 123?

The numbers are 39, 41 and 43.


Three consecutive numbers that equal 369?

"Average" number must be 369/3 ie 123 so numbers are 122, 123 and 124


The sum of three consecutive odd integers is 363 what are the numbers?

The sum of three consecutive odd integers, starting with N, is expressed as N + (N+2) + (N+4). If that sum is 363, then you have 3N + 6 = 363. Solve for N and you have 119.Since N (119) is odd, the answer and question are valid. (If N had been even, the question would have been invalid, and the answer would have been meaningless. This test is simply a sanity check.) The three numbers are 119, 121, and 123.


What is the sum of the consecutive integers from 23 to 123?

7272 * * * * * WRONG! Sum from 23 to 123 = (sum from 1 to 123) minus (sum from 1 to 22) = 123*124/2 - 22*23/2 = 7626 - 253 = 7373. NOT 7272!


What are three consecutive odd integers that have a sum of 123?

39, 41, 43 Let x represent the smallest of these numbers. From the problem, we know x+(x+2)+(x+4)=123 Solving for x: 3x+6=123 3x=117 x=117/3=39 So our integers are: 39, 41, 43


What is the sum of three consecutive integers is -123?

Algebraically. X = integer. X + (X + 1) + (X + 2) = - 123 3X + 3 = - 123 3X = - 126 X = - 42 X + 1 = - 41 X + 2 = - 40 - 42 + - 42 + - 40 = -123 =======