Q: What are the three consecutive integers whose sum of 123?

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39,41,43! Ya

114 115 116 117 118 119 120 121 122 123 124 125 126

Assume we want to determine the integers that multiply to obtain -24.Here are the possible pairs:-1 and 241 and 242 and -12-2 and 123 and -8-3 and 84 and -66 and -4

Answer is 123. Pattern: the difference between the consecutive numbers are multiplied by 3. In this case, the diff is 1 (3 minus 2), 3 (6 minus 3), 9, 27, and 81... and so on...

The square root of 123 = ±11.090537

Related questions

The integers are 40, 41 and 42.

The numbers are 39, 41 and 43.

They are: -39 -41 -43 = -123

123/3 = 41 so integers are 39, 41 and 43

There are no consecutive even integers totaling 123 but there are two combinations of odd/even integers. They are 39, 41 and 43 as well as 40, 41 and 42.

123/3 - 2, 123/3 and 123/3 + 2 ie 39, 41 and 43.

There is a set of two consecutive integers that have a sum of 123; one odd and one even. They are 61 and 62.

x is lowest of the integers so x + (x + 2) + (x + 4) = 123 ie 3x + 6 = 123 so 3x = 117 and x = 39, so integers are 39, 41 and 43

between which two consecutive integers does the square root lie 123

39,41,43! Ya

The numbers are 121, 122 and 123.

61 & 62