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Q: What are the three odd consecutive numbers of 33?

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The numbers are 31, 33 and 35.

The numbers are 33, 35 and 37.

they are 29 31 33

They are 9, 11 and 13.

The numbers are 33 and 35.

let the number be n-1, n, n+1 then 3n=99 and so n=33 the numbers are 32, 33, 34

93/3 = 31 so the three numbers are 31-2, 31 and 31+2 that is, 29, 31 and 33.

Consecutive even numbers are any even numbers which are separated by one (uneven) number... so that 6 and 8 are consecutive even numbers... as are 22, 24 and 26. Similarly, consecutive odd numbers are numbers which are separated by one (even) number... so that 11 and 13 are consecutive odd numbers... as are 31, 33 and 35.

33 & 35.

33/3 = 11 so the three are 9, 11 and 13

Do you mean:"What three consecutive numbers add up to 99?" If you do, then the numbers are 32, 33, 34.

-33 + -33 + -29 = -93

They are: 10+11+12 = 33

The numbers must average 33, so the answer is 32, 33 and 34.

31, 32 and 33.

33, 35, and 37

31, 33, 35

There are no consecutive odd integers whose sum is equal to 35. 9+11+13 = 33, and 11+13+15 = 39.

31, 32, and 33 add up to 96.

-33, -31, -29

Divide the sum of the three consecutive odd integers by 3: 93 / 3 = 31. The smallest of these integers will be two less than 31 and the largest will be two more than 31, so the three consecutive odd integers will be 29, 31, and 33.

The numbers are 9, 11 and 13.

31 + 32 + 33 = 96

The numbers are 31, 32 and 33.

33, 34 and 35.