Q: What are the two consecutive integers with a sum of 58?

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The integers are even and are 28 and 30.

-30 and -28

28,30

Thanks for sharing. The integers are 58 and 60.

The numbers are 56 and 58.

58, 59, 60

They are: 57+58+59 = 174

10,12

57 and 58.

The numbers are 56, 57 and 58.

56+57+58=171

28 + 30 = 58

58, 60, 62, 64

Let x be the smallest of the consecutive odd integers. Since consecutive odd integers differ by 2, we havex + (x + 2) + (x + 4) + (x + 6) = -2204x + 12 = -220 (subtract 12 to both sides)4x = -232 (divide by 4 to both sides)x = -58Thus, the four consecutive odd integers whose sum is -220 are -58, -56, -54, and -52.

To work this sort of problem out we need to divide the number given by the number of integers being sought (in that case two) 118 ÷ 2 = 59. So the two numbers will average 59 and they must be consecutive and even, that means that they must be 1 above and 1 below 59..... 58 and 60. 58 + 60 = 118

Algebraically. X = integers.X + (X + 1) = 592X + 1 = 592X = 58X = 29X + 1 = 30(29, 30)=======

59 + 60 + 61 = 180 ---- To work out consecutive integers, use this formula: (x+1) + (x+2) + (x+3) = 180 ---> 3x + 6 = 180 ---> 3x = 174 ---> 174/3 = x = 58 so (58+1) = 59, (58 + 2) = 60, (58 + 3) = 61

answer is : 58,59working: x= first number, x + 1= second numberx + x + 1 =1172x= 116x= 58

They are: 57+58+59 = 174

Call the lowest of the even integers n. Then from the problem statement, n + n + 2 + n + 4 = n + 6 =244. Collecting like terms results in 4n + 12 = 244, or 4n = 244 - 12 = 232, or n = 232/4 or 58. The consecutive even integers are therefore, 58, 60, 62, and 64.

The answer is 58. 56+57+58 = 171 171 is the largest palindrome less than 220 that can be divided by three. Further palindromes are: 181, 191, 202 and 212.

121

58, 60 and 62.

The average is 58 so, sum(m...n)/33=58. You can think of this as 58 being the middle marker for the consecutive set of numbers which leaves 32 other number, with 16 on one side of 58 and 16 on the other side. So 58-16=42 and 58+16=74. Therefore your consecutive number set is sum(42...74)/33 and so the smallest of these is 42.

180/3 = 60 so the three are 58, 60 and 62

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