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When the smaller of two consecutive integers is added to five times the larger the result is 53. Find the integers?
6x + 5 = 53 6x = 48 x = 8 8 + 45 = 53 8 and 9
When the smaller of two consecutive integers is added to three times the larger result is 23?
this is a algebraic word problem: we know we have two consecutive integers so x + 1 = y and we know that the smaller one (x) added to three times the larger, the results is 23 so x + 3y = 23 substitute (x+1) for y: x + 3(x+1) = 23 4x + 3 = 23 4x = 20 x = 5 y = 6
When the smaller of the two consecutive integers is added to three times the larger the result is 47 Find the integers?
Let the integers be n and n + 1.n + 3(n+ 1) = 47 4n + 3 = 47 4n = 44 n = 11 n+ 1 = 12.
When the smaller of two consecutive integers is added to three times the larger the result is 31 find the integer?
Let x equal the smaller integer. Three times the larger is 3(x + 1) or 3x + 3. Added all together, 4x + 3 = 31. Solve for x. 4x = 28 x = 7 Check it. 7 + 24 = 31 It checks.
When the smaller of two consecutive integers is added to three times the larger the result is 23 find the integer?
Let the integers by 'm' & 'm+1' m +3(m+1) = 23 m + 3m + 3 = 23 4m = 20 m = 5 Hence m+1 = 6
What are two consecutive integers such that the smaller added to two times the larger gives a sum of 16?
There are no such integers.
When the smaller of two consecutive integers is added to five times the larger the result is 65?
The integers are 10 and 11.
When the smaller of two consecutive integers is added to three times the larger the result is 51. Find the integers?
12 and 13.
When the smaller of two consecutive integers is added to two times the larger the result is 17 find the integers?
They are 5 and 6 because 5+(2*6) = 17
When the smaller of two consecutive integers is added to four times the larger the result is 59?
Let the smaller be n, then the larger is n+1; and: n + 4(n+1) = 59 → n + 4n + 4 = 59 → 5n = 55 → n = 11 → the two consecutive integers are 11 and 12.
When the smaller of two consecutive integers is added to five times the larger the result is 53. Find the integers?
6x + 5 = 53 6x = 48 x = 8 8 + 45 = 53 8 and 9
What are two consecutive odd integers that when twice the larger is added to the small the result is 169?
55 and 57
When the smaller of two integers is added to three times the larger the result is 51. Find the integers?
12 and 13.
When the smaller of two consecutive integers is added to five times the larger the result is 53 find the integers?
x+5(x+1)=53 6x+5=53 6x=48 x=8 numbers=8 and 9
When the smaller of two consecutive integers is added to three times the larger result is 23?
this is a algebraic word problem: we know we have two consecutive integers so x + 1 = y and we know that the smaller one (x) added to three times the larger, the results is 23 so x + 3y = 23 substitute (x+1) for y: x + 3(x+1) = 23 4x + 3 = 23 4x = 20 x = 5 y = 6
When the smaller of two consecutive integers is added to three times the larger the result is 43 find the integers?
Suppose the smaller integer is x, then the larger one is x+1. x + 3*(x+1) = 43 That is x + 3x + 3 = 43 so that 4x = 40 and that implies that x = 10 and so the other integer is 11.
What consecutive numbers are equal to 8?
Consecutive integers added or subtracted will turn out to be odd numbers. You can't make 8 with consecutive integers.
