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4 and 5 are the two digits making the number 45.
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∙ 14y ago
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How many digits are in the quotient 45 divided by 3?
15
A two digit number is five times the sum of the digits if 9 is added to the number the digits are reversed find the number?
45
What two digit number is 5 times the sum of its digits?
Answer: 45 4 + 5 = 9 x 5 = 45
A no consist of 2 digits the sum of two digits is 13 it the digits change their places the new no so obtain45 more than original no find out the original no?
49 ( + 45 = 94)
23 is a consecutive two digit number Are there other two digit numbers using consecutive digits?
34, 45 etc.
The sum of the digits of a two-digit number is 9 if the digits are reversed the new number is 9 more than the original number?
Possibility of two digit no whose sum is 9 18,27,36,45,54,63,72,81 Now add 9 to each no mentioned above 27,36,45,54,63,72,81,90 See after 3rd comma 45 and 54. reverse of 45 is 54. 54 is 9 more than 45. So 45 is the original
The sum of the digits of a two digit number is 9 If the digits were reversed the new number would be 9 more than the original number Find the original number?
Possibility of two digit no whose sum is 9 18,27,36,45,54,63,72,91 Now add 9 to each no mentioned above 27,36,45,54,63,72,91,100 See after third comma 45 and 54. If you reverse 45 it will be 54. which is 9 more than 45. So original no is 45
The sum of the digits of a two-digit number is 9 If the digits were reversed the new number would be 9 more than the original number Find the original number?
Possibility of two digit no whose sum is 9 18,27,36,45,54,63,72,81 Now add 9 to each no mentioned above 27,36,45,54,63,72,81,90 See after third comma 45 and 54. Reverse of 45 is 54. 54 is 9 more than the no 45. So 45 is original
There is a number that is 5 times the sum of its digits What is this number?
The number is 45. The sum of its digits i.e. 4+5=9 Five times the sum of its digits i.e. 5 times 9 which is 45
The sum of the digits in a two digit number is 9 If the digits are reversed the new number will be 9 less than the original number What is the original number?
Possibility of two digit no whose sum is 9 18,27,36,45,54,63,72,81 Subract 9 with each no mentioned above output is 9,18,27,36,45,54,63,72 See after 4th comma 54 and 45. Reverse 54=45. now 45 is 9 less than 54. So the original no is 54
How do you write the greatest place value position in which the digits are different for 45 48?
48, 45
The sum of the digits in a two digit number is 11 If the digits are reversed the new number will be 45 less than the original number What is the original number?
Possibility of two digit no whose sum is 11 Are 29,38,47,56,65,74,83,92 Subract 45 to each no mentioned above -16,-7,2,11,20,29,38,47 See after 6th comma 83 and 38 Reverse of 83 is 38. The no 38 is 45 less than 83. Original no is=83
