Possibility of two digit no whose sum is 9
18,27,36,45,54,63,72,81
Subract 9 with each no mentioned above output is
9,18,27,36,45,54,63,72
See after 4th comma 54 and 45. Reverse 54=45. now 45 is 9 less than 54. So the original no is 54
100000 2847239582
Possibility of two digit no whose sum is 10 Are 19,28,37,46,55,64,73,82,91 Add 72 to each no mentioned above output is 91,100,109,118,127,136,145,154,163 See first 19 and 91 Assume that two digit no as 19 reverse it 91 will come. The no 92 is 72 more than 19 So 19 is the original
2178
78 Good guess, but 7 + 8 = 15, not 9; so that answer is incorrect. The correct answer is 54. 5 + 4 = 9 45 is 9 less than 54. * * * * * If the sum of the digits of a 2-digit number is 9, and if the order of the digits is reversed the new number will be a multiple of 9 different from the original. It could be bigger or smaller, and the difference could be 18 or 27. For example, 7+2 = 9 and 72 -27 = 45 (which is not 9 but a multiple of 9)
whats the answer please??
17
The number is 36
47 Impossible problem!
Find a four digit number whose digits will be reversed when multiplied by nine?
192
To total 17 the two digits must be 8 and 9! The original number was 98.
If the number with the digits reversed can have a leading 0 so that it is a 1-digit number, then 16. Otherwise 13.
"If the units digit and the hundreds digit of the number 513 were reversed..." 315 'find the sum of the original number and the new number." 513+315=828
An eight digit number with one zero cannot remain the same when its digits are reversed. It must have an even number of 0s.
45
A) If a number has two digits, then the sum of its digits is less than the value of the original two-digit number.
100000 2847239582