5x2 + 9x + 4 = (x + 1)(5x + 4).
(5x - 1)(x + 3)5x2 + 14x - 3= 5x2 + 15x - x - 3= 5x(x + 3) - 1(x + 3)= (5x - 1)(x + 3)
(x + 1)(5x - 1)
5x2-46x+9 = (5x-1)(x-9)
5x2+ 7x + 2 = (x + 1)(5x + 2).
-5x2+9x-4 -5x2+9x+-4 Factors of -20 that add to equal 9 are -5 and-4 -5x2+5x+4x+-4 -5x(1x+1) + 4x(1+-1x)
5x2+11x+2 = (5x+1)(x+2) when factored
5x2 + 2x - 3 = 0 5x2 + 5x - 3x - 3 = 0 5x(x + 1) - 3(x + 1) = 0 (5x - 3)(x + 1) = 0 So 5x - 3 = 0 or x + 1 = 0 ie x = 3/5 or x = -1
5x2+14x-3 -15. 15*-15x2-x+15x-3[5xx x] [3*5x 3]x(5x-1)+3(5x-3)Answer: (5x-1)(x+3)
(5x - 1)(x + 3)
5x2+7x = 12 5x2+7x-12 = 0 (5x+12)(x-1) = 0 x = -12/5 or x = 1
I am assuming the question is to factor this problem? 5x2 + 29x - 6 (5x - 1)(x + 6)