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What is the factor for the trinomial 5x square plus 11x plus 2?
Wiki User
∙ 13y ago
5x2+11x+2 = (5x+1)(x+2) when factored
Wiki User
∙ 13y ago
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Is a Correct factorization of this trinomial -4x2 plus 11x-6?
It is: -4x^2 +11x -6 equals (-4x+3)(x-2) when factored
Factor the trinomial x2 plus 11x plus 24?
24 = 2 x 12 or 3 x 8 or 4 x 6: Only 3 & 8 total 11 so factors are (x + 8)(x + 3)
What is the factorization of this trinomial -x2 - 11x plus 26?
-x2 - 11x + 26 = -(x2 + 11x - 26) = -(x2 - 2x + 13x - 26) = -[ x(x - 2) + 13(x - 2) ] = -(x + 13)(x - 2) = (x + 13)(2 - x)
What is the factorization of the trinomial x2 11x - 26?
Do you mean x2+11x-26 if so then it is (x-2)(x+13) when factored
How do you factor 9x2 plus 11x-14?
9x2+11x-14 = (9x-7)(x+2) when factored with the help of the quadratic equation formula.
What is factorization of this trinomial -4x plus 11x - 6?
(-4x + 3)(x - 2)Apex :)!!
Is a Correct factorization of this trinomial -4x2 plus 11x-6?
It is: -4x^2 +11x -6 equals (-4x+3)(x-2) when factored
Factor this polynomial completely x plus 11x plus 30?
x+11x+30(x+5)(x+6)
Factor the trinomial x2 plus 11x plus 24?
24 = 2 x 12 or 3 x 8 or 4 x 6: Only 3 & 8 total 11 so factors are (x + 8)(x + 3)
Factor x2 plus 11x-12?
Assuming the question is written as: x2+11x-12 This would factor to: (x+12)(x-1)
What is the factorization of this trinomial -x2 - 11x plus 26?
-x2 - 11x + 26 = -(x2 + 11x - 26) = -(x2 - 2x + 13x - 26) = -[ x(x - 2) + 13(x - 2) ] = -(x + 13)(x - 2) = (x + 13)(2 - x)
How do you factor 11xsquared plus 25x - 24?
(11x - 8)(x + 3)
How do you factor -35x2-11x plus 6?
-(5x + 3)(7x - 2)
What is the factorization of the trinomial x2 11x - 26?
Do you mean x2+11x-26 if so then it is (x-2)(x+13) when factored
What is the factorization of the trinomial -x2 - 11x 26?
-(x + 13)(x - 2)
Will x squared plus 11x 10 factor completely?
I assume you mean...,X2 + 11X + 10(X + 1)(X + 10)==============factored
How do you factor 9x2 plus 11x-14?
9x2+11x-14 = (9x-7)(x+2) when factored with the help of the quadratic equation formula.
