31 + 32 + 33 = 96
94+95+96 96
31 32 33
The numbers are 31, 32 and 33.
If three consecutive integers have the sum of 96, then the problem can be expressed with the equation... N + (N+1) + (N+2) = 96 ...Simplify that and solve and you get... 3N + 3 = 96 3N = 93 N = 31 ... so the three integers are 31, 32, and 33.
31+32+33 = 96
31, 32 and 33
The three consecutive numbers whose sum is 294 are 96, 98 and 100. Also, 97, 98 and 99.
-31, -32, -33
31, 32, 33
To figure this out, divide 96 by three, ignoring the remainder for now. This gives the number 30. The remainder is 6. Three consecutive numbers that add up to six are 1, 2 and 3. So the three consecutive integers are 31, 32, and 33.
Divide 96 by 3= 32 your three numbers are now: 32 -1 = 31 32 = 32 32 + 1=33 31 + 32 +33 = 96