There are infinitely many possible solutions.
Select ANY number, A, greater than 7.5
and let B = 15 - A
Then B is different from A and
A + B = A + 15 - A = 15
Since there are infinitely many possible values for A, there are infinitely many solutions.
19
16 x 15 / 2 ie 120
7
The two numbers are -2 and -15
The two numbers you are looking for are -15 and 4. When you multiply -15 and 4, you get -60, and when you add them together, you get -13.
The two numbers you are looking for are 8 and 15. When you multiply them, 8 × 15 equals 120, and when you add them, 8 + 15 equals 23. However, there's an error in the conditions provided since no two numbers can multiply to 120 and add to 43.
The two numbers that multiply to -30 and add up to 13 are 15 and -2. When you multiply 15 and -2, you get -30, and when you add them together, you get 13.
Three numbers that add up to 50 could be 10, 20, and 20. Another example could be 15, 15, and 20. There are countless combinations, but all must total 50 when summed together.
13 and 2
The two numbers that multiply to -15 and add up to 2 are 5 and -3. When you multiply 5 and -3, you get -15, and when you add them together, you get 2.
-23
The three odd numbers that add up to 43 are 13, 15, and 15. This is because 13 + 15 + 15 = 43. These numbers are odd because they are not divisible by 2, and their sum equals 43, satisfying the condition of the question.