Let the first of the consecutive integers be x. Since the consecutive integers differ by 1, the second one would be x + 1. From the given information we have:
x + (x + 1)2 = -1
x + x2 + 2x + 1 = -1
x2 + 3x + 1 = -1 (add 1 to both sides)
x2 + 3x + 2 = 0
(x + 2)(x + 1) = 0
x + 2 = 0 or x + 1 = 0
x = -2 or x = -1
x + 1 = -2 + 1 = -1 or x + 1 = -1 + 1 = 0
Thus, the two consecutive numbers that satisfy the given condition are -2 and -1, or -1 and 0.
No, it is not possible.
24. The second is 26.
The sum of the first four non-negative, consecutive, even integers is 20.
-7
The first integer is 17.
No, it is not possible.
24. The second is 26.
Consecutive means one after another.If the first is a, then the second is a+1.The sum of these isa + a + 1 = 2a+1 = -3772a = -378a = -189So the two numbers are -189 and -188
The sum of the first four non-negative, consecutive, even integers is 20.
10-11-12
-7
The first integer is 17.
I assume you mean what are the two consecutive integers. Algebraically; X = integers.X + (X + 1) = 2752X + 1 = 2752X = 274X = 137============solution setorSince the consecutive integers differ by 1, then the first number is 274/2 = 137, so the second one is 1 more, 138.
Consecutive integers could be thought of as counting numbers in a row. One of them is "lowest" and the next one will be one more than that, and the last one will be one more than the second one. The numbers 7, 8 and 9 and 46, 47 and 48 are each said to be three consecutive integers. You often come across a question that tells you that 3 consecutive integers add up to a value. Example 3 consecutive integers add to 6. What are the integers? Let the first integer be x the second is then x +1 the third x+2 add them x+x+1+x+2 =3x+3 and this would be equal to 6. we then have the equation 3x+3=6 3x=3 x=1 so the first integer is 1, the second would be 2 and the third 3
18, 20 and 22
If the first of these consecutive integers is x, the second integer would be x + 1, and the third integer would be x + 2.Since the sum of the second and the third integer is 17, we can writex + 1 + x + 2 = 172x + 3 = 172x + 3 - 3 = 17 - 32x = 142x/2 = 14/2x = 7Thus, the consecutive integers are 7, 8, and 9.
Their sum is 99.