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FIND Three consecutive integers such that the sum of the second and the third is 17 Which equation would be used to solve this word problem?
If the first of these consecutive integers is x, the second integer would be x + 1, and the third integer would be x + 2.
Since the sum of the second and the third integer is 17, we can write
x + 1 + x + 2 = 17
2x + 3 = 17
2x + 3 - 3 = 17 - 3
2x = 14
2x/2 = 14/2
x = 7
Thus, the consecutive integers are 7, 8, and 9.
What else can I help you with?
What three consecutive positive even integers such that the product of the second and third integers is twenty more than ten times the first integer?
10-11-12
What are 4 consecutive integers of the sum of 182?
Let's represent the four consecutive integers as x, x+1, x+2, and x+3. The sum of these integers can be expressed as x + (x+1) + (x+2) + (x+3) = 4x + 6. We are given that this sum is equal to 182, so we can set up the equation 4x + 6 = 182. Solving for x, we find x = 44. Therefore, the four consecutive integers are 44, 45, 46, and 47.
The sum of two consecutive even integers is 86 Find the larger number?
If two consecutive numbers add up to 86 then we can set up an equation like this: x=the first number So it makes sense that x+2=the second number (since the numbers are consecutive) And you know the sum of the two is 86. So the resulting equation is (x) + (x+2) = 86 => 2x + 2 = 86 2x = 84 x = 42 So the two numbers are 42 and 44.
Find four consecutive integers such that the sum of the second and fourth is 132 show the work?
Let the first consecutive integer be x. So that:the second integer is x + 1,the third integer is x + 2, andthe fourth integer is x + 3.We have:(x + 1) + (x + 3) = 1322x + 4 = 1322x = 128x = 64 the first integerThus, the four consecutive integers are 64, 65, 66, and 67.
What two consecutive odd integers sum is 176?
First, an equation is needed. We will designate the first integer as N, and the second as N + 2. The sum of the two numbers is 176, so the equation should look like this:N + N + 2 = 176Now it needs to be added:2N + 2 = 176Now both sides need to be subtracted by 2:2N = 174Now both sides need to be divided by 2:N = 87Therefore, the first integer is 87. Since the second integer is designated by N + 2, and N is equal to 87, the second integer is 87 plus 2, which is equal to 89.So the two consecutive odd integers whose sum is 176, are 87 and 89.
Given 3 consecutive integers with a sum of four times the second number write an algebraic equation?
i dont now
What is the equation for this The sum of two consecutive integers in 71?
Let x represent the first integer. The second consecutive integer is then x + 1. The equation can be written as x + (x + 1) = 71.
What is the second integer if three consecutive integers have the sum of 153?
51
How do you find consecutive integers?
Consecutive integers could be thought of as counting numbers in a row. One of them is "lowest" and the next one will be one more than that, and the last one will be one more than the second one. The numbers 7, 8 and 9 and 46, 47 and 48 are each said to be three consecutive integers. You often come across a question that tells you that 3 consecutive integers add up to a value. Example 3 consecutive integers add to 6. What are the integers? Let the first integer be x the second is then x +1 the third x+2 add them x+x+1+x+2 =3x+3 and this would be equal to 6. we then have the equation 3x+3=6 3x=3 x=1 so the first integer is 1, the second would be 2 and the third 3
The sum of two consecutive even integers is 50 what is the first number?
24. The second is 26.
How do you setup a consecutive integer problem?
the first number is x, the second x+1, third, x+2 and so on.so if the sum of three consecutive integers is 24, the setup would be this:x+x+1+x+2=24if it's consecutive even or odd integers the setup would be x, x+2, x+4,etc.so if the sum of three consecutive odd integers is 21, the setup would be:x+x+2+x+4=21for three or more even consecutive numbers, same setup
Three consecutive odd integers such that four times the sum of the first and second is 7 less than 7 times the third?
Let's call the smallest of the consecutive odd integers x. Then the other ones are x+2 and x+4 respectively, and your equation becomes 4*(x+x+2)+7 = 7*(x+4) which is equivalent to 8x+15=7x+28 or x=13, so the consecutive integers you're looking for are 13, 15 and 17.
Find three consecutive integers whose sum is 21 and show the equation?
Let x be the first integer; x+1 is the second integer and x+2 is the third integer. Add them together as stated in the problem; x+(x+1)+(x+2)=21. 3X+3=21. 3x=18 or x=6; x+1=7 & x+2=8; 6, 7, & 8.
The sum of two consecutive integers is -377 What are the integers?
Consecutive means one after another.If the first is a, then the second is a+1.The sum of these isa + a + 1 = 2a+1 = -3772a = -378a = -189So the two numbers are -189 and -188
Find four consecutive integers such that the sum of the second and fourth is 132?
64 65 66 67
What is the sum of two consecutive integers have the sum of 275?
I assume you mean what are the two consecutive integers. Algebraically; X = integers.X + (X + 1) = 2752X + 1 = 2752X = 274X = 137============solution setorSince the consecutive integers differ by 1, then the first number is 274/2 = 137, so the second one is 1 more, 138.
What three consecutive positive even integers such that the product of the second and third integers is twenty more than ten times the first integer?
10-11-12
