Best Answer

If the first of these consecutive integers is x, the second integer would be x + 1, and the third integer would be x + 2.

Since the sum of the second and the third integer is 17, we can write

x + 1 + x + 2 = 17

2x + 3 = 17

2x + 3 - 3 = 17 - 3

2x = 14

2x/2 = 14/2

x = 7

Thus, the consecutive integers are 7, 8, and 9.

Q: FIND Three consecutive integers such that the sum of the second and the third is 17 Which equation would be used to solve this word problem?

Write your answer...

Submit

Still have questions?

Continue Learning about Other Math

10-11-12

If two consecutive numbers add up to 86 then we can set up an equation like this: x=the first number So it makes sense that x+2=the second number (since the numbers are consecutive) And you know the sum of the two is 86. So the resulting equation is (x) + (x+2) = 86 => 2x + 2 = 86 2x = 84 x = 42 So the two numbers are 42 and 44.

Let the first consecutive integer be x. So that:the second integer is x + 1,the third integer is x + 2, andthe fourth integer is x + 3.We have:(x + 1) + (x + 3) = 1322x + 4 = 1322x = 128x = 64 the first integerThus, the four consecutive integers are 64, 65, 66, and 67.

First, an equation is needed. We will designate the first integer as N, and the second as N + 2. The sum of the two numbers is 176, so the equation should look like this:N + N + 2 = 176Now it needs to be added:2N + 2 = 176Now both sides need to be subtracted by 2:2N = 174Now both sides need to be divided by 2:N = 87Therefore, the first integer is 87. Since the second integer is designated by N + 2, and N is equal to 87, the second integer is 87 plus 2, which is equal to 89.So the two consecutive odd integers whose sum is 176, are 87 and 89.

This doesn't work for integers. Using 7, 8 and 9 comes up with 146 which is the closest you can get.

Related questions

i dont now

Let x represent the first integer. The second consecutive integer is then x + 1. The equation can be written as x + (x + 1) = 71.

51

Consecutive integers could be thought of as counting numbers in a row. One of them is "lowest" and the next one will be one more than that, and the last one will be one more than the second one. The numbers 7, 8 and 9 and 46, 47 and 48 are each said to be three consecutive integers. You often come across a question that tells you that 3 consecutive integers add up to a value. Example 3 consecutive integers add to 6. What are the integers? Let the first integer be x the second is then x +1 the third x+2 add them x+x+1+x+2 =3x+3 and this would be equal to 6. we then have the equation 3x+3=6 3x=3 x=1 so the first integer is 1, the second would be 2 and the third 3

24. The second is 26.

the first number is x, the second x+1, third, x+2 and so on.so if the sum of three consecutive integers is 24, the setup would be this:x+x+1+x+2=24if it's consecutive even or odd integers the setup would be x, x+2, x+4,etc.so if the sum of three consecutive odd integers is 21, the setup would be:x+x+2+x+4=21for three or more even consecutive numbers, same setup

Let's call the smallest of the consecutive odd integers x. Then the other ones are x+2 and x+4 respectively, and your equation becomes 4*(x+x+2)+7 = 7*(x+4) which is equivalent to 8x+15=7x+28 or x=13, so the consecutive integers you're looking for are 13, 15 and 17.

Let x be the first integer; x+1 is the second integer and x+2 is the third integer. Add them together as stated in the problem; x+(x+1)+(x+2)=21. 3X+3=21. 3x=18 or x=6; x+1=7 & x+2=8; 6, 7, & 8.

Consecutive means one after another.If the first is a, then the second is a+1.The sum of these isa + a + 1 = 2a+1 = -3772a = -378a = -189So the two numbers are -189 and -188

64 65 66 67

I assume you mean what are the two consecutive integers. Algebraically; X = integers.X + (X + 1) = 2752X + 1 = 2752X = 274X = 137============solution setorSince the consecutive integers differ by 1, then the first number is 274/2 = 137, so the second one is 1 more, 138.

10-11-12