Want this question answered?
Gram crackers
Given ABE, ADC, BD bisescts angle ABC and BD is parallel to EC prove: Triangle EBC is isoceles
The answer depends on what information you already have. Without that knowledge, you cannot even begin to guess what is additional.
If two triangles have the same shape but one is an enlargement of the other they are said to be similar. The two triangles must be equi-angular. To prove that ∆ABC is similar to ∆XYZ it is necessary to prove one of the following :- 1) Two angles in ∆ABC are equal to two angles in ∆XYZ, since it follows that the third angles will also be equal. 2) The three sides of ∆ABC are proportional to the corresponding sides of ∆XYZ AB/XY = AC/XZ = BC/YZ 3) Two sides in ∆ABC are proportional to two sides in ∆XYZ and the angles included between these sides in each triangle are equal. AB/XY = AC/XZ and angle A = angle X.
The answer depends on what ABC is!
Gram crackers
Asa /sss
ABC
BAD = BCD is the answer i just did it
ASA
Here is the answer to your query. Consider two ∆ABC and ∆PQR. In these two triangles ∠B = ∠Q = 90�, AB = PQ and AC = PR. We can prove the R.H.S congruence rule i.e. to prove ∆ABC ≅ ∆PQR We need the help of SSS congruence rule. We have AB = PQ, and AC = PR So, to prove ∆ABC ≅ ∆PQR in SSS congruence rule we just need to show BC = QR Now, using Pythagoras theorems in ∆ABC and ∆PQR Now, in ∆ABC and ∆PQR AB = PQ, BC = QR, AC = PR ∴ ∆ABC ≅ ∆PQR [Using SSS congruence rule] So, we have AB = PQ, AC = PR, ∠B = ∠Q = 90� and we have proved ∆ABC ≅ ∆PQR. This is proof of R.H.S. congruence rule. Hope! This will help you. Cheers!!!
abc
123......Abc.......123..........abc.......ha
They are congruent when they have 3 identical dimensions and 3 identical interior angles.
Blah blah blah
Suing is one thing. Winning is another.
When ABC is used