How do you prove rhs congruence?

Answer 1

Here is the answer to your query.

Consider two ∆ABC and ∆PQR. In these two triangles ∠B = ∠Q = 90�, AB = PQ and AC = PR.

We can prove the R.H.S congruence rule i.e. to prove ∆ABC ≅ ∆PQR

We need the help of SSS congruence rule.

We have AB = PQ, and AC = PR

So, to prove ∆ABC ≅ ∆PQR in SSS congruence rule we just need to show BC = QR

Now, using Pythagoras theorems in ∆ABC and ∆PQR

Now, in ∆ABC and ∆PQR

AB = PQ, BC = QR, AC = PR

∴ ∆ABC ≅ ∆PQR [Using SSS congruence rule]

So, we have AB = PQ, AC = PR, ∠B = ∠Q = 90� and we have proved ∆ABC ≅ ∆PQR. This is proof of R.H.S. congruence rule.

Hope! This will help you.

Cheers!!!