20 is the only number.
It is: 20 to the nearest 10
decimal[] a = new decimal[20]; // initialize to some numbers for (int i = 0; i < 20; i++) { a[i] = i; } Array.Sort(a); //sorted in increasing order Array.Reverse(a); // decreasing foreach (decimal d in a) { Console.WriteLine(d); }
Assuming nerest is your attempt to spell nearest, the answer is that such a number cannot exist. Between any two real numbers, there are infinitely many real numbers. So, between 65 and any number claiming to be nearest, there are infinitely many numbers.
Yes, but only if there are no digits after the decimal point. For example, 18, 19, 20, 21 are consecutive numbers in the decimal system.
20 is a number above the decimal point, so writing it as a decimal is not really possible. You could write 20.0 and include the next numbers place, but it's the same number.
Let the two decimal numbers be x and y. We can set up the equation x - y = 16.825. To find two numbers that satisfy this equation, we can choose any value for x and then subtract 16.825 to find y. For example, if we let x = 20, then y = 20 - 16.825 = 3.175. Therefore, the two decimal numbers are 20 and 3.175.
250 is the nerest ten
20
Whole numbers are a proper subset of decimal numbers. All whole numbers are decimal numbers but not all decimal numbers are whole numbers.
The binary representations of the decimal numbers from 20 to 30 are as follows: 20: 10100 21: 10101 22: 10110 23: 10111 24: 11000 25: 11001 26: 11010 27: 11011 28: 11100 29: 11101 30: 11110 These binary numbers represent their respective decimal values.
Any amount of numbers can be in a decimal.
.2 You don't need to include the zero unless there are numbers after it in a decimal.