There is no such number.
The largest possible remainder when dividing by any number N is N-1.
Suppose you have a number N and you want to find its largest prime factor. It is probably easiest to start at the bottom.Find the smallest prime factor, p.Find its factor pair = N/p.If the second number (= N/p) is a prime, then it is the largest prime factor.if not, replace N by N/p and go back to the top.
A triangle number has the form n(n+1)2 for some positive integer n.then when you substitute n=44 then it is 990 which is largest triangular number before hundred.
The largest is 30. Let the largest of the four consecutive even numbers be n; then the four consecutive even numbers are (n - 6), (n - 4), (n - 2) & n, and: ((n - 6) + (n - 4) + (n - 2) + n) ÷ 4 = 27 ⇒ (4n - 12) ÷ 4 = 27 ⇒ n - 3 = 27 ⇒ n = 30
The number four.
Because given any whole number n, n+1 is a larger whole number. And that process can go on for ever.
No it is not a Thabit number. The definition of the series is 3*2^n-1 and so using n = 4 the thabit number is 47 and where n = 5 the Thabit number is 95. As the Thabit numbers are defined as integers of n then 59 cannot be a Thabit number.
#include<stdio.h> #include<conio.h> main() { int n,max=0,rem; printf("\n enter a number"); scanf("%d",&n); while(n!=0) { rem=n%10; n=n/10; if(rem>max) { max=rem: }} printf("\n the largest digit is: %d",max); getch(); }
The definition of a perfect cube is the cube of a number n is its third power. This is formula that is used for finding volume.
It is the number that is added, subtracted, times, or divide in a pattern to (n) or the start number.
A whole number following immediately after another whole number, like 3 follows 2.
12