87 is already divisible by 3, so you could add a 0, 3, 6 or 9 anywhere in there and get the same result.
I don't completely understand the question, but there's a trick: A number is divisible by 3 if and only if the sum of its digits is divisible by 3. This should guide you to an answer.
29 is not divisible by 3 and how any digit will alter that depends on how that digit is to interact with 29.
numbers divisible to 87 = 3, 29, 87
Converse:If a number is divisible by 3, then every number of a digit is divisible by three. Inverse: If every digit of a number is not divisible by 3 then the number is not divisible by 3? Contrapositive:If a number is not divisible by 3, then every number of a digit is not divisible by three.
no. it is divisible by 3 (87/3=29)
a 3 digit number that is divisible by on is a three digit number that is a multiple of one.
No single digit determines divisibility by 3.
no
To determine what digit can be placed in the blank to make a number divisible by 3, you need to ensure that the sum of all the digits in the number, including the blank, is divisible by 3. For example, if the number is 25_, you would calculate the sum of 2 + 5 + _ and check which digit (0-9) makes the total divisible by 3. Once you find the appropriate digit, you can fill in the blank.
There are 180 3-digit numbers divisible by five.
To make a number divisible by 10, its last digit must be 0. The last digit of 23483 is 3. Therefore, to make it divisible by 10, you should subtract 3 from 23483. This means the least number that should be subtracted is 3.
There are 151 3-digit numbers that are divisible by 6.