All 2 digit numbers are divisible by 7: it is simply that some of the quotients are not whole numbers. 10/7 = 1 3/7 99/7 = 14 1/7 So the number of 2-digit numbers which are evenly divisible by 7 are 14-1 = 13.
There are five such numbers: 11, 12, 15, 24 and 36.
For example you have two numbers 4 and 5 and we add them the result is 9 which is also divisible by 3 if we divide it by 3 the result will be. So it means that total/addition of all the numbers which after addition can be divisible by 3.
All the numbers divisible by 5 are the numbers ending with the digit 5 or 0. The first ten examples are: 5, 10, 15, 20, 25, 30, 35, 40, 45, 50
All the even numbers are divisible by 2.
Not all of them are.
None. Extremely simple proof: To be divisible by 5 the units digit must be 5. But then it would not be divisible by 2.
Trick question all numbers are divisible by four ,but only 175 result in whole numbered answers
Even numbers are divisible by two, and half of all numbers are even, so there is a 50 percent chance that a four-digit number is divisible by two.
All 4 digit numbers that are divisible by 9 are also divisible by 3. The first is 1008 and the last is 9999.
945
one 5 all others are divisible by 5 at least
Select all the numbers that $4221462$ is divisible by.
3, 6, 9
i don't know help
All whole numbers are divisible by 1. Numbers are divisible by 2 if they end in 2, 4, 6, 8 or 0. Numbers are divisible by 3 if the sum of their digits is divisible by 3. Numbers are divisible by 4 if the last two digits of the number are divisible by 4. Numbers are divisible by 5 if the last digit of the number is either 5 or 0. Numbers are divisible by 6 if they are divisible by 2 and 3. Numbers are divisible by 9 if the sum of their digits is equal to 9 or a multiple of 9. Numbers are divisible by 10 if the last digit of the number is 0.
There are three such numbers: 12, 24 and 36.