Any integer divisible by 9 has digits whose sum is divisible by 9. The sum of the digits in 2530 is 2+5+3+0 = 10, and the sum of 1+0 = 1. Having an additional digit "8" in the number, or replacing the "0" with an "8", would make a number divisible by 9. Thus 82,530; 28,530; 25,830; 25,380; 25,308; or 2,538 are all divisible by 9.
99996
To make a number divisible by 10, its last digit must be 0. The last digit of 23483 is 3. Therefore, to make it divisible by 10, you should subtract 3 from 23483. This means the least number that should be subtracted is 3.
No single digit determines divisibility by 3.
The 3, to the left.
4: to make it 90144 = 15024*6
29 is not divisible by 3 and how any digit will alter that depends on how that digit is to interact with 29.
99996
It depends on whether you mean the highest digit that you add or subtract or multiply by!
To make a number divisible by 10, its last digit must be 0. The last digit of 23483 is 3. Therefore, to make it divisible by 10, you should subtract 3 from 23483. This means the least number that should be subtracted is 3.
6 (or 0)
No single digit determines divisibility by 3.
The 3, to the left.
There is no digit that can replace the ? in 2?67 to make it divisible by 4. All multiples of 4 are even, 2?67 is an odd number and so cannot be a multiple of 4.
123456
4: to make it 90144 = 15024*6
0.
1