Q: Find the smallest digit that can be placed in the blank to make 294 786 divisible by 6?

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Let's assume, or hope, that the blank is after those numbers. 67_ and 45_ For a number to be divisible by three, the total of the number's digits has to be divisible by three. 672 and 450

2. To test a number to be divisible by 3, add up the digits and if the sum is divisible by 3, so is the original number. If not, the excess over a multiple of 3 gives the remainder when the original number is divided by 3. Subtract this remainder from 3 and this gives the smallest digit to replace the blank; unless the remainder is 0, in which case the blank can be replaced by a 0: 8 + 6 + 9 + 3 + 5 = 31 → 31 ÷ 3 = 10 remainder 1 Replace blank by 3 - 1 = 2: 826935 is divisible by 3

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