Any integer divisible by 9 has digits whose sum is divisible by 9. The sum of the digits in 2530 is 2+5+3+0 = 10, and the sum of 1+0 = 1. Having an additional digit "8" in the number, or replacing the "0" with an "8", would make a number divisible by 9. Thus 82,530; 28,530; 25,830; 25,380; 25,308; or 2,538 are all divisible by 9.
To determine what digit can be placed in the blank to make a number divisible by 3, you need to ensure that the sum of all the digits in the number, including the blank, is divisible by 3. For example, if the number is 25_, you would calculate the sum of 2 + 5 + _ and check which digit (0-9) makes the total divisible by 3. Once you find the appropriate digit, you can fill in the blank.
To determine what digit to add to 13678 to make it divisible by 4, we need to look at the last two digits, which are 78. A number is divisible by 4 if the number formed by its last two digits is divisible by 4. Since 78 divided by 4 gives a remainder of 2, we can add 2 to 78 to get 80, which is divisible by 4. Therefore, adding the digit 2 to the end of 13678 makes it 136782, which is divisible by 4.
99996
To make a number divisible by 10, its last digit must be 0. The last digit of 23483 is 3. Therefore, to make it divisible by 10, you should subtract 3 from 23483. This means the least number that should be subtracted is 3.
To determine the missing digit that makes a number divisible by 9, you need to ensure that the sum of the digits is divisible by 9. For divisibility by 7 and 1, any number is divisible by 1, and for 7, you can test the entire number (including the missing digit) against divisibility rules for 7. Without specific numbers provided, it's not possible to identify the exact missing digit, so you would need to apply these rules to the specific numbers in question.
29 is not divisible by 3 and how any digit will alter that depends on how that digit is to interact with 29.
To determine what digit can be placed in the blank to make a number divisible by 3, you need to ensure that the sum of all the digits in the number, including the blank, is divisible by 3. For example, if the number is 25_, you would calculate the sum of 2 + 5 + _ and check which digit (0-9) makes the total divisible by 3. Once you find the appropriate digit, you can fill in the blank.
To determine what digit to add to 13678 to make it divisible by 4, we need to look at the last two digits, which are 78. A number is divisible by 4 if the number formed by its last two digits is divisible by 4. Since 78 divided by 4 gives a remainder of 2, we can add 2 to 78 to get 80, which is divisible by 4. Therefore, adding the digit 2 to the end of 13678 makes it 136782, which is divisible by 4.
99996
To make a number divisible by 10, its last digit must be 0. The last digit of 23483 is 3. Therefore, to make it divisible by 10, you should subtract 3 from 23483. This means the least number that should be subtracted is 3.
It depends on whether you mean the highest digit that you add or subtract or multiply by!
To determine the missing digit that makes a number divisible by 9, you need to ensure that the sum of the digits is divisible by 9. For divisibility by 7 and 1, any number is divisible by 1, and for 7, you can test the entire number (including the missing digit) against divisibility rules for 7. Without specific numbers provided, it's not possible to identify the exact missing digit, so you would need to apply these rules to the specific numbers in question.
6 (or 0)
No single digit determines divisibility by 3.
The 3, to the left.
There is no digit that can replace the ? in 2?67 to make it divisible by 4. All multiples of 4 are even, 2?67 is an odd number and so cannot be a multiple of 4.
123456