Q: What digits can be placed in the blank in 56 8 9 to make it divisible by 3?

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If the number is divisible by 9 the sum of its digits (its digital root) must be divisible by 9. 5+6+8+9 = 28 The next multiple of 9 is 36 and that is 8 more. So the missing digit must be 8.

shut up and do something better with your life

No single digit determines divisibility by 3.

A solution.

342 is divisible by 6 and not 5.Numbers divisible by 5 end in zeros or fivesNumbers divisible by 6 have a slightly more complicated rule. If, when the individual digits are added together and they make a multiple of 3, see if the number is even. If so, and the digits add up to a multiple of 3, then the number is a divisible by 6.

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If the number is divisible by 9 the sum of its digits (its digital root) must be divisible by 9. 5+6+8+9 = 28 The next multiple of 9 is 36 and that is 8 more. So the missing digit must be 8.

0.

shut up and do something better with your life

I don't completely understand the question, but there's a trick: A number is divisible by 3 if and only if the sum of its digits is divisible by 3. This should guide you to an answer.

Any number divisible by 3 has digits that add up to a multiple of 3. Adding a 1 to any of these digits or inserting a 1 anywhere in the number would make it divisible by 3.

A solution.

No single digit determines divisibility by 3.

In mathematical logic, An integer A if divisible by 100 iff the last two digits are 0. "iff" stands for "if and only if".

The 5 should be deleted.

342 is divisible by 6 and not 5.Numbers divisible by 5 end in zeros or fivesNumbers divisible by 6 have a slightly more complicated rule. If, when the individual digits are added together and they make a multiple of 3, see if the number is even. If so, and the digits add up to a multiple of 3, then the number is a divisible by 6.

6

That number is 462.