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What number should be added to 39065 to make it divisible by 9?
the rule for divisibility by 9 is that the sum of all digits of the number should should be divisible by 9. So, 3+9+0+6+5= 23. To make is divisible by 9, we think of 27 (as the next number divisible by 9) and that means if we add 4 to any digit of the number, it will be divisible. 39069/9=4341
What digit can be placed 87 and 2 to make each number divisible by 3?
I don't completely understand the question, but there's a trick: A number is divisible by 3 if and only if the sum of its digits is divisible by 3. This should guide you to an answer.
How do you know if 54132 is divisible by 6?
To determine if a number is divisible by 6, it must be divisible by both 2 and 3. To determine if a number is divisible by 2, it should be even - in other words, it should end with 0, 2, 4, 6, or 8. To determine if a number is divisible by 3, the sum of its digits should be divisible by 3. 54,132 is an even number, so it is divisible by 2. 5 + 4 + 1 + 3 + 2 = 15, which is divisible by 3, so 54,132 is divisible by 3. Since 54,132 is divisible by both 2 and 3, it is divisible by 6.
What is the divisibility rule for 27?
Subtract 8 times the last digit from remaining truncated number. Repeat the step as necessary. If the absolute of result is divisible by 27, the original number is also divisible by 27 Check for 945: 94-(8*5)=54; 5-(8*4)=-27 Since 27 is divisible by 27, the original no. 945 is also divisible. Check for 264681: 26468-(8*1)=26460; 2646-(8*8)=2582; 264-(8*6)=216 21-(8*6)=-27 Since 27 is divisible by 27, the original no. 264681 is also divisible. Check for 81: 8-(8*1)=0; Since 0 is divisible by 27, the original no. 81 is also divisible.
Which digits should come in place of and if the no 62684 is divisible by both 8 and 5?
For a number to be divisible by both 8 and 5 then : 1) the final digit must be zero (as a multiple of 5 ending in 5 is not divisible by 8) 2) As 1000 is divisible by 8 then only the last 3 digits of the number need to be checked to confirm if it is divisible by 8. 680 ÷ 8 = 85. Therefore the number has to be changed to 62680 to be divisible by both 8 and 5. Therefore, replace the digit 4 in 62684 with 0.
Which digits should come in place of and if the number 62684 is divisible by both 8 and 5?
Sol. Since the given number is divisible by 5, so 0 or 5 must come in place of $. But, a number ending with 5 is never divisible by 8. So, 0 will replace $. Now, the number formed by the last three digits is 4*0, which becomes divisible by 8, if * is replaced by 4. Hence, digits in place of * and $ are 4 and 0 respectively.
What number should be added to 39065 to make it divisible by 9?
the rule for divisibility by 9 is that the sum of all digits of the number should should be divisible by 9. So, 3+9+0+6+5= 23. To make is divisible by 9, we think of 27 (as the next number divisible by 9) and that means if we add 4 to any digit of the number, it will be divisible. 39069/9=4341
What digit can be placed 87 and 2 to make each number divisible by 3?
I don't completely understand the question, but there's a trick: A number is divisible by 3 if and only if the sum of its digits is divisible by 3. This should guide you to an answer.
How do you know if 54132 is divisible by 6?
To determine if a number is divisible by 6, it must be divisible by both 2 and 3. To determine if a number is divisible by 2, it should be even - in other words, it should end with 0, 2, 4, 6, or 8. To determine if a number is divisible by 3, the sum of its digits should be divisible by 3. 54,132 is an even number, so it is divisible by 2. 5 + 4 + 1 + 3 + 2 = 15, which is divisible by 3, so 54,132 is divisible by 3. Since 54,132 is divisible by both 2 and 3, it is divisible by 6.
Which digits should come in place of and if the no 62684 is divisible by both 8 and 5?
For a number to be divisible by both 8 and 5 then : 1) the final digit must be zero (as a multiple of 5 ending in 5 is not divisible by 8) 2) As 1000 is divisible by 8 then only the last 3 digits of the number need to be checked to confirm if it is divisible by 8. 680 ÷ 8 = 85. Therefore the number has to be changed to 62680 to be divisible by both 8 and 5. Therefore, replace the digit 4 in 62684 with 0.
What is the division rule for 4?
If the last two digits of a number are divisible by 4, the entire number is divisible by 4. The reason this works is because 100 is a multiple of 4.For a number to be divisible by 4, the number formed by the last two digits should be divisible by 4.For example:324 is divisible by 4 because the last two digits put together are 24, and 24/6=4337 is not divisible by 4 because the last two digits put together are 37, and 37 cannot be divided by 4.
Is 1003 a multiple of 3?
No. You should add up all the digits, and if the sum isn't divisible by 3, then the whole number isn't divisible by 3.
Is 4089 divisible by 9?
To check divisibility of 9, add the digits together. add the digits again if your answer has 2 or more digits. you should get 9 as the remaining digit to be divisible by 9. 4 + 0 + 8 + 9 = 21 2 + 1 = 3 So 4089 is not divisible by 9.
Is 414 equally divisible by 3?
I think the question is mistyped, and should be "Is 414 evenly divisible by 3?" i.e. does it divide by 3 without leaving a remainder. The answer is yes. A quick way to tell if a number is divisible by 3 is to add the digits and if the total is divisible by 3, then the number in question is also divisible by 3 4 + 1 + 4 = 9 and 9 is divisible by 3 414 ÷ 3 = 138
Is 705 divisible by 9?
A number is divisible by nine if the sum of the digit foms a number that is multiple of nine table . So this number 705 can be check by like this way : 7+0+5= 12 is not found on the multiplication of nine , so it does not divisible by nine.
How do you Test if a number is divisible by 3?
To check if a number is divisible by another number, we divide. When we divide, there cannot be a remainder. For example, is 9 divisible by 3? Yes, it is because 9 divided by 3 is 3 without a remainder. How about 4? No, because when we divide 4 by 3 there is a remainder of 1. nycfunction@yahoo.com sum of the numbers in the given digits should be divisible by 3.then we can say that it is divisible by 3.example :22344 is divisible by 3.since2+2+3+4+4=15.so the given digit is divisible by 3
Which digits should come in place of and if the no62684 id divisible by both 8 and 5?
The last digit should be 0.
