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If the number is divisible by 9 the sum of its digits (its digital root) must be divisible by 9.

5+6+8+9 = 28

The next multiple of 9 is 36 and that is 8 more. So the missing digit must be 8.

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โˆ™ 2011-01-05 17:54:43
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A polynomial of degree zero is a constant term

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Q: What digits can be placed in the blank in 56 8 9 to make it divisible by 9?
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