657
49 + c units
a + b + c = 180 b = 3a c = 5a Substituting the values of b and c into the first equation. a + 3a + 5a = 180 or 9a = 180 so that a = 20 then b = 3a = 3*20 = 60 and c = 5a = 5*20 = 100
5 digits in a zip code
x = b/(a + c)
If: a = 2b+c Then: a-c = 2b And: b = (a-c)/2
Assuming A, B, C and D all represent different digits then ABC = 183 .
And how does this relate to coins?
a - b = c -(a - b) = -c b - a = -c
a= (+a) or a= (-) b= 2a b= 2a c= (-a) c= (+a)
2a. (a, b and c are all equal.)
A.
:-)
A=B , A-B=B-B , A-B =0 B=C , B-B=C-B, 0=C-B So A-B=0 but also C-B=0 A-B=C-B ...add +b ...A-B+B=C-B+B , A=C
by transitive property
Yes.
a = 20 b = 60 c = 100
A=0 b=0 c=0