28 inch square
The perimeter is 28.
If the rectangle has a width of x inches, and a length of x + 16 inches, then its perimeter equals to 2x + 2x + 32 or 4x + 32. If x = 14, then x + 16 = 30. So the perimeter of rectangle becomes 2(14) + 2(30) = 28 + 60 = 88 inches.
When figuring out what number goes both into 21 and 28, you should look at the factor paris. 21: 1 x 21, 3 x 7 28: 1, 28, 2 x 14, 4 x 7 7 goes into both 21 and 28.
If the width is seven on both sides and the length is seven on both sides then the perimeter is 7+7+7+7 = 28.
Area = 0.5*21*28 = 294 square inches
28*21 equals 84
28 times 21 equals 588.
Area = 0.5*21*28 = 294 square inches
Yes
3x + 7 = -4x + 28 implies 7x + 7 = 28
21 + 7 = 28 28 / 4 = 7 Your answer is 7.
294 in^2
The area is 294 square inches.
Let the length of the longest side of the triangle be x units.Since the lengths of the sides of the triangle are consecutive even numbers, which differ by 2, the perimeter of the triangle equals to (x - 4) + (x - 2) + x = 3x - 6.Since the length of the longest side is 22 units shorter than the perimeter, the perimeter of the triangle also equals to x + 22. So that3x - 6 = x + 22 (subtract x and add 6 to both sides)3x - x + 6 - 6 = x - x + 6 + 222x = 28 (divide both sides by 2)x = 14Thus the longest side has a length of 14 units.
3a - 7 = -28 Therefore, 3a = -21 a = -21/3 Therefore, a = -7
28 inch square