HCF(63, 35) = 7
9
First, clearly, 4 divides into 252, yielding 63. Then, it becomes evident that 9 and 7 divide in, thus prime factored to:7 * 32 * 22.
First, compute the least common multiple of 7 and 9. lcm(7,9) = (7*9)/gcd(7,9) where gcd(7,9) is the greatest, common divisor of 7 and 9, that is the largest number that divides both numbers. In this case, the gcd is 1. So, lcm(7,9)=7*9=63 So we want to find a multiple of 63 between 200 and 300 Note that 63 < 300-200 = 100. So we must be able to find a number in between 200 and 300 that is a multiple of 63. Now we divide 200 by 63 to get 3.174603.... Since 200/63 = 3.174603 < 4 (rounding up to the nearest integer) It follows that 200/63 < 4 and then 200 < 63*4 Since 7, and 9 both divide 63, it follows they both divide 63*4 So the answer is: 252
75.15 divides by 15.12 = 4.970238095238096
63 will divide any multiple of 63, that is, any number of the form 63*k where k is an integer.
HCF(63, 35) = 7
9
Any non-zero number does.
441 divides evenly by these numbers: 1 3 7 9 21 49 63 147 and 441.
It is 7.
Yes, because 7 divides evenly into 63 with no remainder.
Yes, because 7 divides evenly into 42 with no remainder.
Community Answer 1Yes, because 7 divides evenly into 63 with no remainder.Community Answer 2Yes because 9*7 = 63
The GCF of 49 and 63 is 7. The greatest common factor is the highest number that divides exactly into two or more numbers. 49: 1, 7, 49 63: 1, 3, 7, 9, 21, 63
21. 63 = 32 x 7 84 = 22 x 3 x 7 hcf = 3 x 7 = 21
567 divides by these numbers: 1, 3, 7, 9, 21, 27, 63, 81, 189, 567.