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What is the largest number which divides exactly into both 63 and 35?
HCF(63, 35) = 7
What is the largest integer that divides evenly into 63 and 27?
9
What is the HCF of 63 and 21?
The Highest Common Factor (HCF) of 63 and 21 is 21. To find the HCF, you can list the factors of both numbers and find the highest number that divides both evenly. In this case, the factors of 63 are 1, 3, 7, 9, 21, and 63, while the factors of 21 are 1, 3, 7, and 21. The highest number that appears in both lists is 21, making it the HCF.
What is the prime factorization of 252 in exponents?
First, clearly, 4 divides into 252, yielding 63. Then, it becomes evident that 9 and 7 divide in, thus prime factored to:7 * 32 * 22.
What number is divisible by 7 and 9 and in between 200 and 300?
First, compute the least common multiple of 7 and 9. lcm(7,9) = (7*9)/gcd(7,9) where gcd(7,9) is the greatest, common divisor of 7 and 9, that is the largest number that divides both numbers. In this case, the gcd is 1. So, lcm(7,9)=7*9=63 So we want to find a multiple of 63 between 200 and 300 Note that 63 < 300-200 = 100. So we must be able to find a number in between 200 and 300 that is a multiple of 63. Now we divide 200 by 63 to get 3.174603.... Since 200/63 = 3.174603 < 4 (rounding up to the nearest integer) It follows that 200/63 < 4 and then 200 < 63*4 Since 7, and 9 both divide 63, it follows they both divide 63*4 So the answer is: 252
