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A division equation in which the numerator is an integer multiple of the denominator.

Q: What division equation has no remainder?

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13/954 = 0 with remainder 13.

You cannot write the quotient itself as an equation, but you can express a division operation and use an equation to express that the result of this operation (the quotient) is a specific value. For example, 16/8 =2.

It's called the remainder

16.6

12.0123

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13/954 = 0 with remainder 13.

You cannot write the quotient itself as an equation, but you can express a division operation and use an equation to express that the result of this operation (the quotient) is a specific value. For example, 16/8 =2.

It's called the remainder

Quotient = Dividend / Divisor Quotient is the answer to the equation (3 = 6 / 2, the quotient is 3). Dividend is what you are dividing (3 = 6 / 2, the dividend is 6). Divior is what you are dividing by (3 = 6 / 2, the divisor is 2). If division equation is changed to 3 = 7 / 2, we have a remainder of 1 left from the dividend.

16.6

An oblique asymptote is another way of saying "slant asymptote."When the degree of the numerator is one greater than the denominator, an equation has a slant asymptote. You divide the numerator by the denominator, and get a value. Sometimes, the division pops out a remainder, but ignore that, and take the answer minus the remainder. Make your "adapted answer" equal to yand that is your asymptote equation. To graph the equation, plug values.

the remainder

12.0123

You do not invert it. However, you can convert the remainder to a decimal by carrying out a long division of the remainder divided by the original divisor. For example, 13/3 = 4r1 Then, long division of the remainder (=1) by the divisor (=3) gives 0.33.... which is the converted remainder. The full quotient, in decimal form is 4.33...

To check for divisibility, use the "%" operator - the remainder of a division. If the remainder is 0, it is divisible.for (i = 1; i

Division BY 76: 75 Division of 76: 76

If the divisor of a division problem is 4, any number between 0 and 3 (inclusive) can be a remainder for that problem.