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Q: What divisors can you get a remainder of 8 when you divide a 3 digit by a 1 digit and why?

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im sorry but i can t figure it out

12, 6, 4, 3, 2, and 1 are the divisors of 12 because these numbers divide 12 without leaving any remainder.

You repetitively divide the number by two, taking the remainder as the digit (in binary). When you divide by 2, the remainder will either be 0 or 1.Example: convert 23 (base 10) to binary:23/2 = 11, remainder 1 (this is the ones digit)11/2 = 5, remainder 1 (this is the twos digit)5/2 = 2, remainder 1, (this is the fours digit)2/1 = 1, remainder 0, (this is the eights digit)1/2 = 0, remainder 1, (this is the sixteens digit). So now combine the digits (sixteens is the highest digit in this number):23 (base 10) = 10111 (base 2)

The single-digit divisors of 7,000 are 1, 2, 4, 5, 7, 8.

You divide when there is a remainder the same as you divide when there is none. The only difference is that when you divide the last digit in the dividend, you will wither add a decimal point and 0 to the right of the digit and keep dividing, designate the leftover number as a remainder, or you will put the remainder over the divisor to show the remainder as a fraction. For example: 761 divided by 10 is 76 with a remainder of 1. You can write 76 R1, 76 1/10 or 76.1

The single-digit divisors of 12,300 are: 1, 2, 3, 4, 5, 6.

Regardless of the dividend (the number being divided), no divisor can produce a remainder equal to, or greater than, itself..... dividing by 4 cannot result in a remainder of 5, for example, Therefore the only single-digit number which can return a remainder of 8 is 9. 35 ÷ 9 = 3 and remainder 8

Find the quotient

The single-digit divisors of 27,000 are: 1, 2, 3, 4, 5, 6, 8, 9.

The single-digit divisors of 3,456 are: 1, 2, 3, 4, 6, 8 and 9.

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