The sum of interior angles are: (28-2)*180 = 4680 degrees
sum of interior angles of a regular polygon = (n-2) x 180 degrees, where n = number of sides. Each interior angle - sum of exterior angles / the total number of angles (and there are the same number of angles as sides, so you can use sum / n) = ((28-2)*180)/28) = (26*180 / 28) = 4680 / 28 = 167.1429 degrees
The angles of what?
(2 x 16 - 4) right angles = 28 right angles = 28 x 90 = 2520 degrees
name all vertcal angles name all vertcal angles
The interior angles add up to 4680 degrees
The sum of the interior angles of a polygon with n sides is 180o × (n - 2), consequently the sum of the interior angles of a 28-sided polygon is 4680o (180o × 26).
alternate angles
The other 2 angles are c 62 and 90 degrees
28
90 degree angles
right angles or 90 degrees