sum of interior angles of a regular polygon = (n-2) x 180 degrees, where n = number of sides.
Each interior angle - sum of exterior angles / the total number of angles (and there are the same number of angles as sides, so you can use sum / n)
= ((28-2)*180)/28)
= (26*180 / 28)
= 4680 / 28
= 167.1429 degrees
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It is a triacontagon, or 30-sided shape.The formula for one interior angle of a regular n-sided polygon is 180(n-2)/nwhere 180 (28) / 30 = 168*You can QUICKLY and EASILY find the answer using the formula for one exterior angle : it is 360/n360/30 = 12 and the interior angle is 180-12 = 168.The algebraic equation is(180-168) n = 360
The easiest way to calculate this is to calculate the exterior angle and use the fact that the exterior and interior angles are supplementary. Sum exterior angles = 360° → Each exterior angle of a regular 28-agon is 360° ÷ 28 → Each interior angle of a regular 28-agon = 180° - 360° ÷ 28 = 167 1/7° ≈ 167.14°
A 30 sided polygon contains 28 triangles.
cocokragon
28 of them located at each vertex