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sum of interior angles of a regular polygon = (n-2) x 180 degrees, where n = number of sides.
Each interior angle - sum of exterior angles / the total number of angles (and there are the same number of angles as sides, so you can use sum / n)
= ((28-2)*180)/28)
= (26*180 / 28)
= 4680 / 28
= 167.1429 degrees
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If an interior angle of a regular polygon is 168 degrees what is the name of the polygon?
It is a triacontagon, or 30-sided shape.The formula for one interior angle of a regular n-sided polygon is 180(n-2)/nwhere 180 (28) / 30 = 168*You can QUICKLY and EASILY find the answer using the formula for one exterior angle : it is 360/n360/30 = 12 and the interior angle is 180-12 = 168.The algebraic equation is(180-168) n = 360
What is the size of each interior angle of a regular polygon with 28 sides?
The easiest way to calculate this is to calculate the exterior angle and use the fact that the exterior and interior angles are supplementary. Sum exterior angles = 360° → Each exterior angle of a regular 28-agon is 360° ÷ 28 → Each interior angle of a regular 28-agon = 180° - 360° ÷ 28 = 167 1/7° ≈ 167.14°
How many triangles does a 30 sided polygon contain?
A 30 sided polygon contains 28 triangles.
What is the name of a 28 sided polygon?
cocokragon
How many vertices are there in a 28 sided polygon?
28 of them located at each vertex
What is the sum of the interior angle measures of a 28 sided polygon?
The interior angles add up to 4680 degrees
What is the size of each interior angle in a polygon with 28 sides?
Providing that it is a regular 28 sided polgon then each interior angle will measure: 1670 8' 34.29''
What is the exterior angle of a 28 sided polygon?
12.4567890
What is each angle size in a 28 sided polygon?
If it's a regular 28-agon then each interior angle is: (26*180)/28 = 167.'142857' degrees recurring decimals 0.'142857'
What is the sum of angles in a 28-sided polygon?
The sum of the interior angles of a polygon with n sides is 180o × (n - 2), consequently the sum of the interior angles of a 28-sided polygon is 4680o (180o × 26).
If an interior angle of a regular polygon is 168 degrees what is the name of the polygon?
It is a triacontagon, or 30-sided shape.The formula for one interior angle of a regular n-sided polygon is 180(n-2)/nwhere 180 (28) / 30 = 168*You can QUICKLY and EASILY find the answer using the formula for one exterior angle : it is 360/n360/30 = 12 and the interior angle is 180-12 = 168.The algebraic equation is(180-168) n = 360
What is the sum of the interior angles of a 28-gon?
For an n-sided regular polygon, the sum of the interior angles is equal to 180 x (n - 2). In the case of a 28-sided polygon, this would be 180 x (28 - 2) = 180 x 26 = 4680 degrees.
What is a 28 sided angle called?
A 28 sided polygon is called an Icosikaioctagon This link should help: http://www.math.com/tables/geometry/polygons.htm
What is the sum in the measure of degrees of the interior angles of a 16-sided polygon?
Sum of interior angles of ANY n-sided polygon is (2n - 4) right angles. In this case 28 x 90 ie 2520o
What is the measure of the interior and exterior angle of a 16-gon?
Assuming regular figure, exterior angle of n-sided polygon = 360/n degrees. In this case n = 16 so angle is 22.5 degrees and interior is 180 minus that figure ie 157.5 degrees. Alternatively you can use the formula for sum of interior angles of regular n-sided polygon which is (2n - 4) right angles. In this case 2n - 4 = 28 right angles which is 2520 degrees. Divided by 16 gives 157.5 degrees.
What is the size of each interior angle of a regular polygon with 28 sides?
The easiest way to calculate this is to calculate the exterior angle and use the fact that the exterior and interior angles are supplementary. Sum exterior angles = 360° → Each exterior angle of a regular 28-agon is 360° ÷ 28 → Each interior angle of a regular 28-agon = 180° - 360° ÷ 28 = 167 1/7° ≈ 167.14°
How many triangles does a 30 sided polygon contain?
A 30 sided polygon contains 28 triangles.
