You know that the sample space of one die being rolled is
{1,2,3,4,5,6}, if you roll two dice,
you have a sample space with 36 elements. Here it is: (1,1)(1,2)(1,3)(1,4)(1,5)(1,6)(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)
From this we can calculate many probabilities. We could look at the sums. For example what is the probability of rolling two dice and have a sum of 2?
There is only one way out of 36 for this to happen so it is 1/36.
Similarly, what is the chance of rolling a 1 and a 3, in either order?
What is the chance of having a sum of 6? All these answers come directly from
the sample space above.
Not necessarily.
If two six sided fair dice are rolled, the sum of the result of both dice that has the lowest probability to come up is 2 and 12. P(2) = 1/36. P(12) = 1/36.
there are 6 faces of the dice so the answer is 1/6
If you rolled 2 fair dice, the probability of having a sum of 6 is 5 over 36
The probability of rolling 12 with 2 dice is 1 in 36. The probability of not rolling 12 with 2 dice is 35 in 36.
6 ways: 1 and 4, 4 and 1, 2 and 3, 3 and 2, 5 and 0, 0 and 5 A five can be rolled with either dice being a 2,3,4,1 and the other dice being the correlating number that adds to five ie. 4-1, 1-4. 3-2. 2-3. There is no 0 on a die.
If two dice are rolled, the probability that the sum of observed values is equal to 13 is zero. The sum of two dice can only lie between 2 and 12, inclusive.
The lowest number will be obtained by getting lowest number on both of the dice if its a 6 sided dice (normal kind) then the lowest will be 2
The are 36 permutations of two dice. Of these, 6 permutations have the two dice with the same number, specifically 1+1, 2+2, 3+3, 4+4, 5+5, and 6+6. The probability, then, that two dice rolled will not have the same number is 30 in 36, or 5 in 6, or about 0.8333.
It is 1/6.
It is 1/6.
It is 15/36.